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enot [183]
2 years ago
15

-5+(-3).I know the answer is -8 but how because a negative plus a negative is a positive.

Mathematics
1 answer:
ira [324]2 years ago
8 0

Answer:

“two negatives = positive” rule works for multiplication and division.

Step-by-step explanation:

-5 + (-3) example

imagine a number line with 0 in the center. From (0) You move left 5 places to (-5) on the number line. Now you move another 3 more to the left (-3) and land on (-8).

You are combining the negatives. I hope this helps.

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James wants to buy some CDs that cost $14 each and a DVD that costs $23. He has $65. Write an equation (in the Show your work ar
notsponge [240]

Answer:

3

Step-by-step explanation:

65-23= 42

42/14= 3

4 0
3 years ago
Read 2 more answers
If KM = 32 units, KL = 3x+6 and LM= 11 units, what is the value of x?
Rus_ich [418]

Answer:

<h2>x = 5</h2>

Step-by-step explanation:

|<------------------- 32 units ---------------->|

K-----------------------L-------------------------M

           3x + 6                    11

KL + LM = KM

3x + 6 + 11 = 32

3x = 32 - 11 - 6

x = 15 / 3

x = 5 units

7 0
4 years ago
The amount of time that people spend at Grover Hot Springs is normally distributed with a mean of 73 minutes and a standard devi
Vesnalui [34]

Answer:

(a) X\sim N(\mu = 73, \sigma = 16)

(b) 0.7910

(c) 0.0401

(d) 0.6464

Step-by-step explanation:

Let <em>X</em> = amount of time that people spend at Grover Hot Springs.

The random variable <em>X</em> is normally distributed with a mean of 73 minutes and a standard deviation of 16 minutes.

(a)

The distribution of the random variable <em>X</em> is:

X\sim N(\mu = 73, \sigma = 16)

(b)

Compute the probability that a randomly selected person at the hot springs stays longer than 60 minutes as follows:

P(X>60)=P(\frac{X-\mu}{\sigma}>\frac{60-73}{16})\\=P(Z>-0.8125)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly selected person at the hot springs stays longer than an hour is 0.7910.

(c)

Compute the probability that a randomly selected person at the hot springs stays less than 45 minutes as follows:

P(X

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly selected person at the hot springs stays less than 45 minutes is 0.0401.

(d)

Compute the probability that a randomly person spends between 60 and 90 minutes at the hot springs as follows:

P(60

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly person spends between 60 and 90 minutes at the hot springs is 0.6464

6 0
3 years ago
Marta runs a mandarin-orange fruit stand. She is talking to an employee, Maribel, on the phone and trying to tell her the equati
Ivanshal [37]

Answer:

Fifty more than half the number of the oranges is one-hundred-and-twenty.

The sum of fifty and half the number of oranges is the same as one-hundred-twenty.

Step-by-step explanation:

The equation is 50 + one-half m = 120.

Assume the number of oranges=m

50+1/2m=120

1/2m=120-50

1/2m=70

m=70÷1/2

=140

All statement that applies includes:

1. Fifty more than half the number of the oranges is one-hundred-and-twenty.

50+1/2m=120

2. The sum of fifty and half the number of oranges is the same as one-hundred-twenty.

50+1/2m=120

Martha can use the two statements above to communicate the correct equation

8 0
3 years ago
Read 2 more answers
(10.02)
melisa1 [442]

Answer:

sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}

Therefore:

sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}

cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}

Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}

4 0
3 years ago
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