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enot [183]
2 years ago
15

-5+(-3).I know the answer is -8 but how because a negative plus a negative is a positive.

Mathematics
1 answer:
ira [324]2 years ago
8 0

Answer:

“two negatives = positive” rule works for multiplication and division.

Step-by-step explanation:

-5 + (-3) example

imagine a number line with 0 in the center. From (0) You move left 5 places to (-5) on the number line. Now you move another 3 more to the left (-3) and land on (-8).

You are combining the negatives. I hope this helps.

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Suppose a sample of 100 families of four vacationing at Niagara Falls resulted in sample mean of $282.45 spent per day and a sam
Juli2301 [7.4K]

Given Information:

Mean = μ = $282.45

Standard deviation = σ = $64.50

Sample size = n = 100

Confidence level = 95%

Required Information:  

95% Confidence interval = ?

Answer:

95% Confidence interval = ($269.81, $295.09)

Step-by-step explanation:

We are given a Normal Distribution, which is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.

What is Confidence Interval?

The confidence interval represents an interval that we can guarantee that the target variable will be within this interval for a given confidence level.  

The confidence interval is given by

CI = \bar{x} \pm MoE\\

Where \bar{x} is the mean and MoE is the margin of error given by

MoE = z_{\alpha/2}(\frac{\sigma}{\sqrt{n} } ) \\

Where σ is the standard deviation, n is the sample size and z_{\alpha/2} is the z-score corresponding to 95% confidence level.

z_{\alpha/2} = 1 - 0.95 = 0.05/2 = 0.025\\\\z_{0.025} = 1.96

MoE = 1.96\cdot \frac{64.50}{\sqrt{100} } \\\\MoE = 1.96\cdot 6.45\\\\MoE = 12.64\\

Finally, the confidence interval is

CI = \bar{x} \pm MoE\\\\CI = 282.45 \pm 12.64\\\\CI = 282.45 - 12.64 \: and \: 282.45 + 12.64\\\\CI = \$269.81 \: and \:\:\$295.09\\

Therefore, we are 95% sure that the true population mean amount spent per day by a family of four visiting Niagara Falls is within the interval of ($269.81, $295.09)

3 0
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Homework - Pure Year 1 - Chapter 11B
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Answer:

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= 15N i + 8×½N i + 8×√3/2N j

= 15N i + 4N i + 4√3N j

= 19N i + 4√3N j

|F net| = √(19²+(4√3)²) = √(361+48) = √409 ≈ 20.22N

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