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2 years ago

HELP ASAP!!! QUESTION IN PHOTO! MARKING BRAINLIEST

Mathematics

1 answer:

Norma-Jean [14]2 years ago

3 0

What the question on

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2 years ago

Find the product.........................

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Step-by-step explanation:

To find the answer, you have to multiply each term of the first parenthesis' expression with each term in the next parenthesis' expression. Then combine like terms. So we have:

$(6x^2-6x-5)(7x^2+6x-5)\\=(6x^2)(7x^2)+(6x^2)(6x)+(6x^2)(-5)+(-6x)(7x^2)+(-6x)(6x)+(-6x)(-5)+(-5)(7x^2)+(-5)(6x)+(-5)(-5)\\=42x^4+36x^3-30x^2-42x^3-36x^2+30x-35x^2-30x+25\\=42x^4-6x^3-101x^2+25$

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2 years ago

If a club charges dues of $200 a year, it will have 50 members. For each $5 it raises its dues, it loses a member. USE AN EQUATI

Vikentia [17]

Answer:

The value is $y = \$ 225$

Step-by-step explanation:

From the question we are told that

The amount charge per year is $k = \$ 200$

The number of members it will have at this amount is $n = 50$

The amount amount increase that will lead to the loss of a single member is $z = \$ 5$

Generally the total amount the club would obtain from its members is mathematically represented as

$I = Amount \ due\ paid * Number \ of members$

Now let x denote the number of member lost

Hence

$I = (k + zx) (n-x )$

=> $I = (200 + 5x) (50-x )$

=> $I = 10000+50x-5x^2$

Thus the number of members that be removed to give the maximum income from dues is obtained by differentiating the above equation and equating it to zero

$\frac{dI}{dx} = 50-10x$