Step-by-step explanation:
4(x - 7) + 8
= (4)(x) + (4)(-7) + 8
= 4x - 28 + 8. (D)
Since there is no repetition allowed, there are 10 possibilities for the 1st digit, 9 for the 2nd, 8 for the 3rd, and 7 for the 4th. This gives a total of (10)(9)(8)(7) = 5040 four-digit codes.
For all odd digits to be used, there are 5 possibilities for the 1st digit (1,3,5,7,9), 4 for the 2nd, 3 for the 3rd, 2 for the 4th. This gives a total of (5)(4)(3)(2) = 120 codes that only use odd digits.
Therefore there are 5040 - 120 = 4920 codes that do not consist of all odd digits. The probability is 4920/5040 = 41/42.
I need more information to solve this question, comment below
There are 4 quarters in dollars. Keep that in mind.
Since Taylor is spending no more than 17 dollars, she probably only has 17 dollars. We already know that she has 8 dollars in bills, so we can subtract 8 dollars from 17 dollars because we need to find the amount of dollars in quarters.
The answer for that is 9 dollars. Since there are 4 quarters in the dollars, you need to multiply 9 by 4 to find the amount of quarters.
F(-5) x g(-5)
f(-5) = -2(-5) - 7
f(-5) = 10 - 7
f(-5) = 3
g(-5) = -4(-5) + 3
g(-5) = 20 + 3
g(-5) = 23
f(-5) x g(-5) = 3 x 23 = 69
Your answer is 69
