The sum of the first four terms of the sequence is 22.
In this question,
The formula of sum of linear sequence is
The sum of the first ten terms of a linear sequence is 145
⇒ 
⇒ 145 = 5 (2a+9d)
⇒ 
⇒ 29 = 2a + 9d ------- (1)
The sum of the next ten term is 445, so the sum of first twenty terms is
⇒ 145 + 445
⇒ 
⇒ 590 = 10 (2a + 19d)
⇒ 
⇒ 59 = 2a + 19d -------- (2)
Now subtract (2) from (1),
⇒ 30 = 10d
⇒ d = 
⇒ d = 3
Substitute d in (1), we get
⇒ 29 = 2a + 9(3)
⇒ 29 = 2a + 27
⇒ 29 - 27 = 2a
⇒ 2 = 2a
⇒ a = 
⇒ a = 1
Thus, sum of first four terms is
⇒ 
⇒ 
⇒ S₄ = 2(2+9)
⇒ S₄ = 2(11)
⇒ S₄ = 22.
Hence we can conclude that the sum of the first four terms of the sequence is 22.
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The last line of a proof represents <span>the conclusion. The correct option among all the options that are given in the question is the third option or the penultimate option. The other choices can be easily neglected. I hope that this is the answer that has actually come to your desired help.</span>
Answer:
2. 3/4 x 5/9 = 3x5/4x9 = 15/36 = 5/12
4. 4/7 x 1/2 = 4x1/7x2 = 4/14 = 2/7
6. 4/9 x 2/3 = 4x2/9x3=8/27
Step-by-step explanation:
Hope it helps!
Answer:
Below
Step-by-step explanation:
● f(x) = -2x + 3
● f (0) = -2 (0) +3 = 3
● f(-32) = -2(-32)+3 = 64 + 3 = 67
● f(10) = -2(10) +3 = -20 + 3 = -17
● f(-17) = -2(-17) + 3 = 34 + 3 = 37
● f(10) => -17
● f(-17) => 37
Answer:
Equation of line 1 is 3 X - 4 Y = 20
Equation of line 2 is 3 X + 4 Y = 20
Step-by-step explanation:
Given co ordinates of points as,
( -4 , 8) and (0 , 5)
From the given two points we can determine the slop of a line
I. e slop (m) = 
Or, m = 
So, m = 
Now equations of line can be written as ,
Y - y1 = m ( X - x1)
<u>At points ( -4 , 8)</u>
Y - 8 = (X + 4)
So , Equation of line 1 is 3 X - 4 Y = 20
<u>Again with points ( 0 , 5)</u>
Y - 5 = ( X - 0)
So, Equation of line 2 is 3 X + 4 Y = 20
Hence Equation of line 1 is 3 X - 4 Y = 20 and Equation of line 2 is 3 X + 4 Y = 20 Answer
