Answer:
Oh okay then so the answer is 38.
Answer:
c
Step-by-step explanation:
Answer:
a) Attached
b) P=0.60
c) P=0.80
d) The expected flight time is E(t)=122.5
Step-by-step explanation:
The distribution is uniform between 1 hour and 50 minutes (110 min) and 135 min.
The height of the probability function will be:

Then the probability distribution can be defined as:
![f(t)=\frac{1}{25}=0.04 \,\,\,\,\\\\t\in[110,135]](https://tex.z-dn.net/?f=f%28t%29%3D%5Cfrac%7B1%7D%7B25%7D%3D0.04%20%5C%2C%5C%2C%5C%2C%5C%2C%5C%5C%5C%5Ct%5Cin%5B110%2C135%5D)
b) No more than 5 minutes late means the flight time is 125 or less.
The probability of having a flight time of 125 or less is P=0.60:

c) More than 10 minutes late means 130 minutes or more
The probability of having a flight time of 130 or more is P=0.80:

d) The expected flight time is E(t)=122.5

Answer:
27 years old
Step-by-step explanation:
Let Alvin's age be x and Elga's age is y:
y - x = 15
x + y = 27
2y = 42 (use elimination method)
y = 21
x = 6 (plug it back into either equation)
Therefore Alvin is 6 and Elga is 27