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lianna [129]
2 years ago
11

Tammy learns in science class that water freezes when its temperature is

Mathematics
1 answer:
Oksanka [162]2 years ago
7 0

The required number line that shows all of the possible

temperatures is option A.

<h3>Inequalities and number line</h3>

From the given question, we have that water freezes when its temperature is no more than 32 °F

The statement no more than 32 °F shows that the temperature cannot be greater than 32 but less than or equal to 32. This is written mathematically as;

t ≤ 32.

We are to select the number line that shows all of the possible temperatures. The required number line that shows all of the possible

temperatures is option A.

Learn more on number lines here: brainly.com/question/24644930

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Which of the following is the solution to the inequality -5x + 20 &lt; 130?
Masja [62]
The answer is B. x > -22


-5x + 20 < 130

-5x < 130 - 20

-5x < 110

-5x/-5 > 110/-5

x > -22
6 0
2 years ago
Someone please help me with this. thanks. and please explain.
just olya [345]
It would be 190 km because you do 5 x 3 to get 15 add a 0 at the end of it. Than at 40 because .8 of 150 is 40. Then 150+40= 190
4 0
3 years ago
Read 2 more answers
The surface area of a sphere with a diameter of 12 units is:
svetlana [45]

Answer:

Surface area of sphere = 4πr²

r = radius

radius = diameter /2

= 12/2

= 6units

Surface area = 4π×6²

= 144π

= 452.4 square units

Hope this helps.

4 0
3 years ago
Use quadratic regression to find
Rashid [163]

The quadratic equation is given by:

y = 3x² + 10x - 8

The standard equation of a parabola is given by:

y = ax² + bx + c

Where a, b, c are constants

At point (4, 80):

80 = a(4)² + b(4) + c

16a + 4b + c = 80     (1)

At point (-3, -11):

-11 = a(-3)² + b(-3) + c

9a - 3b + c = -11     (2)

At point (-1, -15):

-15 = a(-1)² + b(-1) + c

a - b + c = -15     (3)

Solving equations 1, 2 and 3 simultaneously gives:

a = 3, b = 10, c = -8

Therefore the quadratic equation becomes:

y = 3x² + 10x - 8

Find out more on quadratic equation at: brainly.com/question/1214333

8 0
2 years ago
Can any negative integer be greater than a positive integer explain
Keith_Richards [23]

No, it is impossible. Intuitively, a negative number sits at the left of 0 on the number line, and a positive number sits at the right of 0 on the number line. And a number x is greater than another number y if x sits at the right of y on the number line. So, every positive number is greater than any negative number.

Also, by definition, a positive number is greater than 0, and a negative number is smaller than zero. So, if x is positive and y is negative, you have

y < 0 < x

and since the relation of order "<" is transitive, this implies

y < x

5 0
3 years ago
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