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1 year ago

If f(x)=2(3x-5) when f(x) =74,what is the value of x??

Mathematics

2 answers:

Zinaida [17]1 year ago

8 0

Answer:

x = 14

Step-by-step explanation:

given f(x) = 2(3x - 5) and f(x) = 74 , then equating gives

2(3x - 5) = 74 ( divide both sides by 2 )

3x - 5 = 37 ( add 5 to both sides )

3x = 42 ( divide both sides by 3 )

x = 14

Rom4ik [11]1 year ago

7 0

The answer is 14
Hopefully this helps

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If the rate of decrease for the partial pressure of N2H4 in a closed reaction vessel is 76 torr/h , what is the rate of change f

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The reaction is missing and it's ;

N2H4 + H2 ---> 2NH3

It asks for the total pressure too.

Answer:

A) Rate of change for NH3 = 152 torr/h

B) The total pressure in the vessel will remain the same.

Step-by-step explanation:

N2H4 + H2 ---> 2NH3

1 mole of N2H4 yields 2 moles of NH3.

From the question, the rate given for N2H4 is 76 torr/h.

Thus, The rate of change for NH3 will be = 2 x 76 = 152 torr/h

Now, on the reaction side, 1 mole of N2H4 reacts with 1 mole of H2. So we have 2 moles on the left hand side.

While on the product side, 2 moles of NH3 are produced.

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2 years ago

Sebastian wants to create a right triangle with side lengths 14 inches, 48 inches, and 5

allochka39001 [22]

Answer: Choice A

$\text{Yes, because } 14^2+48^2 \text{ is equal to } 50^2$

=======================================================

Explanation:

The pythagorean theorem is $a^2+b^2 = c^2$

The value of c is always the longest side, aka hypotenuse.

The order of 'a' and b doesn't matter.

So a = 14, b = 48, c = 50

We have $a^2+b^2 = 14^2+48^2 = 196+2304 = 2500$

We also have $c^2 = 50^2 = 2500$

Both sides result in 2500 which proves that $14^2+48^2 = 50^2$ is a true statement. Therefore, we do have a right triangle.

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1 year ago

A plane averaged 800 mph on a trip going east, but only 400 mph on the return trip. The total flying time in both directions wa

galina1969 [7]

Answer:

1200 miles.

Step-by-step explanation:

Let d represent one way distance.

We have been given that a plane averaged 800 mph on a trip going east, but only 400 mph on the return trip.

$\text{Time}=\frac{\text{Distance}}{\text{Speed}}$

The time taken while going east would be $\frac{d}{800}$ .

The time taken while returning back would be $\frac{d}{400}$ .

Since the total flying time in both directions was 4.5 hr, so we will equate sum of both times with 4.5 as:

$\frac{d}{800}+\frac{d}{400}=4.5$

Make a common denominator:

$\frac{d}{800}+\frac{d*2}{400*2}=4.5$

$\frac{d}{800}+\frac{2d}{800}=4.5$

$\frac{d+2d}{800}=4.5$

$\frac{3d}{800}=4.5$

$\frac{3d}{800}\times \frac{800}{3}=4.5\times \frac{800}{3}$

$d=1.5\times \frac{800}{1}$

$d=1200$

Therefore, the one-way distance was 1200 miles.

5 0

2 years ago