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Lelechka [254]
3 years ago
14

I need to find the surface of the figure

Mathematics
2 answers:
pickupchik [31]3 years ago
6 0
PLEASE RATE 5 STARS

Answer: 
360 square meters 
ikadub [295]3 years ago
3 0
360!!!!!!!!!!!!!!!!!!!!
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What is the rule for the given sequence? 3, 8, 23, 68, 203,
EleoNora [17]

Answer: Add the number previously added multiplied by 3;

+3x, where x is the number that was added previously

Step-by-step explanation:

3+5=8. That's the first equation, where 5 is x. Then the next equation, 8+3x=23. 8+15=23. It works for all of the equations, so that's the pattern.

4 0
3 years ago
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Find S15 for the geometric series 72 + 12 + 2 + 1/3 +…
Gemiola [76]
S1 = 72
S2 = 12 = 72*(1/6)
S3 = 2 = 72*(1/6)^2
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S15 = 72*(1/6)^14 = 9.18*10^(-10)
5 0
3 years ago
Which is f(6) for the quadratic function graphed?<br> 0 -2<br> * -0.5<br> 1.5<br> 4
rusak2 [61]

Answer:

4

Step-by-step explanation:

I'm pretty sure theres a graph to this so....

The given parabolic graph of quadratic function

To find:What is F(6) for the quadratic function

Solution:We have given graph of quadratic function

there is a different value for Y and a different value for X

For f(6)

here X=6, need to find graph of quadratic function

X=6

f(6)=4

Y=4

Your welcome :)

4 0
3 years ago
Plot and label all the points that are 4 units from point P AND that share the same x coordinate as point P. Write the coordinat
Lilit [14]
The answers should be: (-2,5), (-2,-2), (-6,-1), (2,1)





Hope this helped :)
7 0
3 years ago
The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

⇒ a = √2304 = 48

For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

5 0
3 years ago
Read 2 more answers
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