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irina [24]
1 year ago
5

write an equation for the line passing through the point (3,5) and perpendicular to the line y=-1/3x+5

Mathematics
1 answer:
jarptica [38.1K]1 year ago
4 0

Answer:

y= 3x -4

Step-by-step explanation:

The equation of a line can be written in the form of y=mx +c, where m is the slope and c is the y-intercept. This is also known as the slope-intercept form.

y =  -  \frac{1}{3} x + 5

Since the given equation is in the slope-intercept form, we can identify its slope from the coefficient of x.

Slope= -⅓

The product of the slopes of perpendicular lines is -1.

Slope of perpendicular line

=  - 1 \div ( -  \frac{1}{3} )

=  -  1 \times ( -  \frac{3}{1} )

= 3

Thus, the equation of the perpendicular line is given by:

y= 3x +c

Substitute a pair of coordinates that the line passes through to find the value of c.

When x= 3, y= 5,

5= 3(3) +c

5= 9 +c

<em>Minus 9 on both sides:</em>

c= 5 -9

c= -4

Hence, the equation of the perpendicular line is y= 3x -4.

Additional:

For more questions on equation of perpendicular lines, do check out the following!

  • brainly.com/question/2141803

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Step-by-step explanation:

Here, we want to write each profit as a positive number and each loss as a negative number

thus, we have that;

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One side of a triangle is two times the second side. The third side is 5 feet longer than the second side. The perimeter of a tr
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2 years ago
the length of a rectangle exceeds its width by 17 inches, and the area is 18 square inches. what are the length and width of the
dimaraw [331]

The length and width of the rectangle are 18 in and 1 in, respectively.

<h3>Quadrilaterals</h3>

There are different types of quadrilaterals, for example, square, rectangle, rhombus, trapezoid, and parallelogram.  Each type is defined accordingly to its length of sides and angles. For example, in a rectangle,  the opposite sides are equal and parallel and their interior angles are equal to 90°.

The area of a rectangle can be found for the formula : b*h, where b = base and h =height.

For this question, the length exceeds its width by 17 inches - L=W+17. Here, the length is the base and the width is the height. Thus,  from the value of area given, you can find the values of the length and width of the rectangle.

A=b*h

18=(W+17)*W

18=W²+17W

W²+17W-18=0

Solving this quadratic equation, you have:

w_{1,\:2}=\frac{-17\pm \sqrt{17^2-4\cdot \:1\cdot \left(-18\right)}}{2\cdot \:1}

w_{1,\:2}=\frac{-17\pm \:19}{2\cdot \:1}

w1=1 and w2= -18

For dimensions, only positive numbers must be used. Then, the width is equal to 1 inch.

As, the area (l*w) is 18 in², see.

18=l*w

18=l*1

l=18 in

Read more about the area of rectangle here:

brainly.com/question/25292087

#SPJ1

5 0
1 year ago
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