3 years ago

PLZ HELP 75 POINTS SHOW WORK

Mathematics

2 answers:

Alexeev081 [22]3 years ago

6 0

Answer:

See in attachment and Mark as brainleist please.

Hope it helps

creativ13 [48]3 years ago

3 0

://us-static.z-11448242604gthis is answer

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Find the slope of the line that passes through (4, 6) and (2, 3).

Verizon [17]

The slope is 3/2

To find the slope, you have to use the slope formula

y2-y1/x2-x1

6-3/4-2

3/2

So the slope is 3/2

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Step-by-step explanation:

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gizmo_the_mogwai [7]

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Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

hence, the limit of the function is -1/14

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3 years ago