The option that describes the relationship between the two confidence intervals is; The width of I₈₁ will be¹/₉ the width of I₉
<h3>How to calculate width of the confidence interval with normal distribution?</h3>
The width of the confidence interval will be calculated from the formula;
W = 2Z(σ/√n)
where;
z is the z-score at given confidence level
σ is standard deviation
n is sample size
For first sample;
W_i9 = 2Z(σ/√9)
W_i9 = ²/₃Zσ
For second Sample;
W_i81 = 2Z(σ/√81)
W_i81 = ²/₉Zσ
Thus, we will have;
W_i9/W_i81 = (²/₃Zσ)/(²/₉Zσ)
W_i9/W_i81 = 9
W_i81 = ¹/₉W_i9
Read more about width of confidence interval at; brainly.com/question/15934877
hope you understand everything , AD.
The complex number represented by the point graphed on the complex plane below is -3-3i
Complex number is generally expressed as z = x + iy
where:
- x is the real axis
- y is the imaginary axis
From the complex plane shown, we can see that the point lies in the Quadrant III of the xy plane.
The coordinate of the point on the plane is given as (-3, -3). This can be represented in complex notation as -3 - 3i
Learn more on complex number here: brainly.com/question/5564133