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4 years ago

Solve the exponential function

Mathematics

1 answer:

nikklg [1K]4 years ago

8 0

Answer:

See below.

Step-by-step explanation:

Just like 18, continue with 19-21. Solve for x by rewriting each equation in log form.

$e^x = 4.9\\\\x = ln 4.9\\\\x = 1.59$

When rewriting the form, the base of the exponent becomes the base of the log.

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3 years ago

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4 years ago

we believe that 42% of freshmen do not visit their counselors regularly. For this year, you would like to obtain a new sample to

Maksim231197 [3]

Answer:

A sample of 1077 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

42% of freshmen do not visit their counselors regularly.

This means that $\pi = 0.42$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

How large of a sample size is required?

A sample size of n is required, and n is found when M = 0.035. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.035 = 2.327\sqrt{\frac{0.42*0.58}{n}}$

$0.035\sqrt{n} = 2.327\sqrt{0.42*0.58}$

$\sqrt{n} = \frac{2.327\sqrt{0.42*0.58}}{0.035}$

$(\sqrt{n})^2 = (\frac{2.327\sqrt{0.42*0.58}}{0.035})^2$

$n = 1076.8$

Rounding up:

A sample of 1077 is required.

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3 years ago

Please help solving this ! Which net represents the figure?

Sergeeva-Olga [200]

Answer:

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Step-by-step explanation:

The net for a figure is a representation of all of the figure's faces. The polygons in the net are joined on an edge corresponding to a common edge between the faces they represent.

The given figure is a rectangular prism. Its faces are only rectangles. All nets that have triangles in the net can be eliminated from consideration.

The appropriate choice is the one attached.

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2 years ago

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4 years ago