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Fudgin [204]
2 years ago
14

Write an equation using x and y to represent the hanger.

Mathematics
2 answers:
avanturin [10]2 years ago
4 0

Answer:

Step-by-step explanation:

Givens

The triangle is x

The square is y

<u>Left side</u>

x + 3y is the weight

<u>Right side</u>

4x + y is the weight.

The weights are equal because the hanger is balanced.

Balance equation

x + 3y = 4x + y                 Subtract x from both sides

x-x + 3y = 4x-x + y           Combine

3y = 3x + y                       Subtract y from both sides

3y - y = 3x + y - y             Combine

2y = 3x

Answer

2y = 3x

weqwewe [10]2 years ago
4 0

Answer:

  x +3y = 4x +y

Step-by-step explanation:

A hanger diagram like this is intended to show you that the total weight on the left side is equal to the total weight on the right side.

__

<h3>left side</h3>

The left side shows 1 triangle and 3 squares. x and y are defined as the weights of the triangle and square, respectively, so the weight on the left side can be represented as ...

  x + 3y

<h3>right side</h3>

The four triangles and 1 square on the right can have their total weight represented as ...

  4x +y

<h3>balance</h3>

The intent of the diagram is to show that the left-side weight is equal to the right-side weight. That equality can be written as ...

  x +3y = 4x +y

_____

<em>Additional comment</em>

This problem is not asking for any sort of "solution" or relationship between x and y. We could find such a relationship by solving the equation for y:

  x +2y = 4x . . . . subtract y from both sides

  2y = 3x . . . . . . . subtract x from both sides

  y = (3/2)x . . . . . divide by the coefficient of y

This tells you that the hanger will only be balanced if the weight of a square is half-again as much as the weight of a triangle.

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