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2 years ago

If a line has a slope of 2 and contains the point (-2, 1), what is its equation in

Mathematics

1 answer:

Lapatulllka [165]2 years ago

5 0

Answer:

Step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b ) a point on the line

here m = 2 and (a, b ) = (- 2, 1 ) , then

y - 1 = 2(x - (- 2)) , that is

y - 1 = 2(x + 2)

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What is the length of the altitude of the equilateral triangle below?

ElenaW [278]

Answer:

Step-by-step explanation:

the height a creates with half of the baseline (5) and a leg (10) a right-angled triangle, and we can use Pythagoras to calculate a.

c² = a² + b²

c being the Hypotenuse (the side opposite of the 90° angle, so in our case the 10 side).

10² = a² + 5²

100 = a² + 25

75 = a²

a = sqrt(75) = sqrt(3×25) = 5×sqrt(3)

5 0

2 years ago

The description for a certain brand of house paint claims a coverage of 460 ft2/gal. (a) express this quantity in square meters

Angelina_Jolie [31]

Given 460 $ft^2/gal$

a) convert it into $m^2/l$

=> It means $ft^2 -> m^2$ and $gal -> l$

1 ft = 0.3048 m

$1 ft^2 = 0.092903 m^2$

1 gal = 3.78541 l

$460ft^2= [tex]460\frac{ft^2}{gal} = \frac{42.7354m^2}{3.78541l} = 11.2895m^2/l$ m^2[/tex].

b. $11.2895\frac{m^{2} }{l} *1000\frac{l}{m^3} =11289.5 m^{-1}$

c.Given= $460\frac{ft^2}{gal}$

To find inverse, divide it by 1.

Inverse- $\frac{1}{460} \frac{gal}{ft^2}$

6 0

4 years ago

Please Help Me! I will give all my point to who ever answers my question!!!

love history [14]

Step-by-step explanation:

The equation that is given is only for the specific place of that object. To find the velocity, you need to take the derivative of the equation. This will give you:

$V=2+\frac{1}{2} t$

Now, to find the average velocity of this object, plug in the values given to you. It's between the time interval [1, 2] so these are the two numbers you'll plug into the velocity equation. Finding this average is like finding any other average.

$V(1)=2+\frac{1}{2} (1)\\V(1)=2+\frac{1}{2}=\frac{5}{2}\\V(2)=2+\frac{1}{2}(2)\\V(2)=2+1=3$

$V_{avg}=\frac{3-\frac{5}{2} }{2-1} \\V_{avg}=\frac{\frac{6}{2}-\frac{5}{2} }{1} \\V_{avg}=\frac{1}{2}$

Average velocity is 0.5 sec

To find instantaneous velocity just find the velocity at time one. Think about the name "instantaneous velocity," it's the velocity in that <u>instant</u>.

We already found this, so I don't need more work (it's displayed above).

The instantaneous velocity when $t=1$ is 2.5 sec.

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3 years ago

Hσw dσ u ѕσlvє thíѕ prσвlєm líkє multíplч вut whєn ѕímplчfíng í gσt lσѕt

Mariana [72]

3/4×2/3= 6/12÷6/6= 1/2

7 0

3 years ago

Given AB = 18, DE = 6, and AD = 5, find<br> the perimeter of ADEF<br> Perimeter =?

anygoal [31]

Answer:

this is my other accont

Step-by-step explanation:

4 0

3 years ago