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2 years ago

Find the domain of the graphed function.

Mathematics

1 answer:

Darya [45]2 years ago

4 0

The domain of the graphed function is [-3, 2)

<h3>How to determine the domain and the range?</h3>

From the given graph, we have the following highlights:

Minimum x value = -3 (closed circle)
Maximum x value = 2 (open circle)

Open circles are represented with () while closed circles are represented with []

Hence, the domain of the graphed function is [-3, 2)

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There was only 5/12 of a pizza left. Carl then ate 1/6 of the remaining pizza. How much of the pizza was left?

eimsori [14]

$\frac{5}{12} - \frac{1}{6} = \frac{5}{12} - \frac{2}{12} = \frac{3}{12} = \frac{1}{4}$

$\frac{1}{4}$ of the pizza was left

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3 years ago

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5. Solve for x using any method you'd like. Round to the hundredth. Show all your work. (2 points each) d. 20x^3 = 7x^5

Sindrei [870]

Solving this equation for x, we have:

$\begin{gathered} 20x^3=7x^5 \\ 7x^5-20x^3=0 \\ x^3(7x^2-20)=0 \\ \begin{cases}x^3=0\to x=0 \\ 7x^2=20\to x=\pm\sqrt[]{\frac{20}{7}}\end{cases} \end{gathered}$

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1 year ago

Math. My brain cells have officially ADIOSED out of my brain.

natima [27]

Answer:

Step-by-step explanation: 40

4 0

3 years ago

If AB vector =(4 5) and PQ vector=(2p 10) are parallel to each other, find the value of p.

Sedaia [141]

Answer:

Answer:

They both have q+3/2p, so that means that 2PQ=CB and that means they are parallel to each other

Step-by-step explanation:

PQ=PA+QA

PQ=1/2(2q-p)+2/5*5p=q-1/2p+2p=q+3/2p

CB=2q+3p=2(q+3/2p)

Other explanation: It should be written like this PQ=q+3/2p and CB=2q+3p=2(q+3/2p) they are parallel bcs CB=2*PQ.

8 0

3 years ago

If f(x) = 8 – 10x and g(x) = 5x + 4, what is the value of (fg)(–2)?

Vedmedyk [2.9K]

F(x) = 8 - 10x

g(x) = 5x + 4

Finding (fg)(-2).

First let us find fg(x), this is the same as f(g(x))

f(g(x))

f(5x + 4)

Recall, f(x) = 8 - 10x, therefore f(5x + 4) would be such that anywhere we see x in the f(x), we replace it with 5x + 4

f(x) = 8 - 10x

f(5x +4) = 8 - 10(5x + 4)

   = 8 - 50x - 40

   = -50x + 8 - 40

   = -50x - 32

f(g(x)) = fg(x) = -50x - 32

fg(-2) = -50*(-2) - 32 = 100 - 32 = 68

Therefore fg(-2) = 68

I hope this helped.

5 0

3 years ago