A ball is thrown vertically upward with an initial speed of 96ft/sec. It’s height after t seconds is given by h=-16(t-3)2 + 144.
1 answer:
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Answer:
m<1 = 121°
m<2 = 59°
Step-by-step explanation:
If m<1 is the supplement of m<2 and the measure of each angle is given:
m<1=2x+65
m<2=3x-25
Find m<1:
When two angles are supplement of each other, there sum is equal to 180°
i.e m<1 + m<2 = 180°
Putting values and finding angle 1
So, we get x=28
Now finding m<1 by putting x=28
Now, finding m<2 by putting x=28
So, we get:
m<1 = 121°
m<2 = 59°