Let x be the whole number. x^2 is the square of the number. x-1 is the preceding number. And x+1 is the following number.
(x+1)(x-1)=
x^2 + x - x - 1
x^2 -1
Your answer is x^2-1 which is one less that x^2. This also means that the square of any whole number (x^2) is one greater than the product of the preceding (x-1) and the following (x+1).
Answer:
Alice: 2184
Maggie:1794
Luna:798 this one is weird cause it has a decimal but u cant have a fraction of a bead so i left it out
Zeinab:1333 same with this one
Step-by-step explanation:
The correct answer is A) {(1, 3), (4, 2), (5, 2), (4, 1} and <span>D) {(1, 2), (4, 3), (1, 5), (5, 6)}.</span>
The center of a circle given the equation in the form (x-h)^2 + (y-k)^2 = r^2 is (h,k). x-8 shows that h is 8, y+2 shows that k is -2, meaning the center is (8, -2)
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