Answer:
4k^3 + k^2 - 2k + 7
Step-by-step explanation:
Hope this helps, and good luck
Given the graph of the function
and the graph of the function
when f(x) = g(x).
This occurs at the point(s) of intersection of the graphs of the function f(x) and g(x).
From the graph, we can approximate the points of intersection of the graphs of the function f(x) and g(x) to pe points
(-1.9, 13.7) and (2.7, 0).
Answer:
whats the question
Step-by-step explanation:
1) The ball's position is described by:
s(t) = 4.9t² + 450
We want to find the velocity, which is the 1st-order derivative of the displacement function (I assume this is an introductory calculus class)
s'(t) = v(t) = 9.8t
We get this by multiplying 4.9 x 2 and reducing the exponent by 1. Now we simply plug 5 in for t.
v(5) = 9.8* 5
v(5) = 49m/s
2) Our cost function is C(x) = x² - 10,000
To find the average rate of change between these units, we use this formula:
( C(101) - C(100) ) ÷1 .
We find the change in C, and divide by the change in x, which is just one.
C(101) = 101² - 10,000
C(101) = 201
C(100) = 100² - 10,000
C(100= 0
C(101) - C(100) = 201
Average rate of change in cost is 201 dollars/ unit between the two points.