21. Given the equation of the circle (x + 3)² + (y-2)² = 16, what is the center and radius of the circle? A (3.2):r = 4 B. (-3,-

Question

ELEN [110]

2 years ago

11

21. Given the equation of the circle (x + 3)² + (y-2)² = 16, what is the center and radius of the circle? A (3.2):r = 4 B. (-3,-

2); r = 8 C. (-3,2); r = 4 D. (3.-2): r=8

Mathematics

2 answers:

Gre4nikov [31] · Answer 1 · 2023-08-13T00:30:25+03:00

Gre4nikov [31]2 years ago

5 0

I’m still laughing so I just got a text back home lol lol sorry I’m not leaving now I have got a new car so I’m sorry buddy can send it back home if it’s

olchik [2.2K] · Answer 2 · 2023-08-13T02:24:11+03:00

Answer:
Letter C (-3,2); r=4

Instructions:
1) You see that the equation is in the correct form. So, now you need to compare this
(x-h)^2 + (y-k)^2=r^2
(x+3)^2+ (y-2)^2=r^16

2) You see that the symbols change in both equations, so - • + = -
X=-3

3) - • - = +
Y=2

4) that is why the center is (-3,2)

5) Now, you need to make a square root of 16
Which is 4 (the number which if you multiply two times ^2, will be 16)