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Alja [10]
2 years ago
11

please help it's 4 am and this is due at 9 am and if you use my points for no reason I'll report you 15 points each

Mathematics
2 answers:
kobusy [5.1K]2 years ago
7 0

Answer:

SA = 244.92² inches

Step-by-step explanation:

Basically just plug in the information given to you into the equation.

π (pi) = 3.14

r (radius) = 3 (radius is 1/2 of diameter, and the diameter is 6; half of 6 is 3 so that is the radius)

h (height) = 10

Therefore your equation set up should look like:

2(3.14)(3²) + 2(3.14)(3)(10) = 244.92

juin [17]2 years ago
4 0

The answer is 8, I’ve seen this exact same question on Brainly before

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Read 2 more answers
13. Determine whether B = {(-1, 1,-1), (1, 0, 2), (1, 1, 0)} is a basis of R3.
Sholpan [36]

Answer:  Yes, the given set of vectors is a basis of R³.

Step-by-step explanation:  We are given to determine whether the following set of three vectors in R³ is a basis of R³ or not :

B = {(-1, 1,-1), (1, 0, 2), (1, 1, 0)} .

For a set to be a basis of R³, the following two conditions must be fulfilled :

(i) The set should contain three vectors, equal to the dimension of R³

and

(ii) the three vectors must be linearly independent.

The first condition is already fulfilled since we have three vectors in set B.

Now, to check the independence, we will find the determinant formed by theses three vectors as rows.

If the value of the determinant is non zero, then the vectors are linearly independent.

The value of the determinant can be found as follows :

D\\\\\\=\begin{vmatrix} -1& 1 & -1\\ 1 & 0 & 2\\ 1 & 1 & 0\end{vmatrix}\\\\\\=-1(0\times0-2\times1)+1(2\times1-1\times0)-1(1\times1-0\times1)\\\\=(-1)\times(-2)+1\times2-1\times1\\\\=2+2-1\\\\=3\neq 0.

Therefore, the determinant is not equal to 0 and so the given set of vectors is linearly independent.

Thus, the given set is a basis of R³.

5 0
3 years ago
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