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PolarNik [594]
2 years ago
12

Figure 1 shows cavity wall insulation being installed in the wall of a house.

Physics
1 answer:
Alexeev081 [22]2 years ago
8 0

Explanation:

Energy loss through walls can be reduced using cavity wall insulation. This involves blowing insulating material into the gap between the brick and the inside wall, which reduces the loss by air circulating inside the cavity, therefore reducing loss by convection through the cavity.

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How do we live on earth if the earth is in the sky?
PtichkaEL [24]

Answer:

We live on earth because we are not floating in the sky.

Explanation:

Because earth may be in the sky but we are not technically we are in the sky on earth not in the sky that's incorrect.

4 0
2 years ago
What are 5 wave interactions with matter?
liberstina [14]
Reflection
Refraction
Diffraction
Transmission
Absorption
8 0
3 years ago
The kinetic energy of a rocket is increased by a factor of eight after its engines are fired, whereas its total mass is reduced
Rudik [331]

The momentum increases by a factor of 2

Explanation:

We can solve this problem by rewriting the momentum of the rocket in terms of the kinetic energy and the mass.

The kinetic energy of the rocket is:

K=\frac{1}{2}mv^2 (1)

where

m is the mass

v is the velocity

The momentum of the rocket is

p=mv (2)

From eq.(1) we get

v=\sqrt{\frac{2K}{m}}

and substituting into (2),

p=\sqrt{2mK}

Now in this problem we have:

- The kinetic energy of the rocket is increased by a factor 8:

K' = 8K

- The mass is reduced by half:

m'=\frac{m}{2}

Substituting, we find the new momentum:

p'=\sqrt{2(\frac{m}{2}(8K)}=\sqrt{4(2mK)}=2\sqrt{2mK}=2p

So, the momentum increases by a factor of 2.

Learn more about momentum and kinetic energy:

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4 0
3 years ago
A radar used to detect the presence of aircraft receives a pulse that has reflected off an object 5 ✕ 10−5 s after it was transm
Sunny_sXe [5.5K]

Answer:

7500 m

Explanation:

The radar emits an electromagnetic wave that travels towards the object and then it is reflected back to the radar.

We can call L the distance between the radar and the object; this means that the electromagnetic wave travels twice this distance, so

d = 2L

In a time of

t=5\cdot 10^{-5}s

Electromagnetic waves travel in a vacuum at the speed of light, which is equal to

c=3.0\cdot 10^8 m/s

Since the electromagnetic wave travels with constant speed, we can use the equation for uniform motion ,so:

d=vt (1)

where

v=c=3.0\cdot 10^8 m/s

t=5\cdot 10^{-5}s

d=2L, where L is the distance between the radar and the object

Re-arranging eq(1) and substituting, we find L:

L=\frac{vt}{2}=\frac{(3.0\cdot 10^8)(5\cdot 10^{-5})}{2}=7500 m

7 0
4 years ago
In one experiment, the teacher determined that the force on the wire was 2.14 mN
blsea [12.9K]

Answer:

in ine experiment the teacher determined

3 0
3 years ago
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