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77julia77 [94]
2 years ago
15

A 23 g bullet traveling at 230 m/s penetrates a 2.0 kg block of wood and emerges cleanly at 170 m/s. If the block is stationary

on a surface with a coefficient of kinetic friction of 0.15 when hit, how far does it move after the bullet emerges?
Physics
1 answer:
Anuta_ua [19.1K]2 years ago
6 0

Answer:

Explanation:

Conservation of momentum during the collision

0.023(230) + 2.0(0.0) = 0.023(170) + 2.0v

v = 0.69 m/s

The initial block kinetic energy will be converted to friction work

½mv² = Fd = μmgd

½(2.0)(0.69²) = 0.15(2.0)(9.8)d

d = 0.1619387... m

d = 16 cm

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What is the average speed of a car that moved 40 km in 3 hours?
Naya [18.7K]

<u>A</u> would be the answer, since it would take about 3 hours to cover most of it, 10km/h would be the average speed.


really hope this helps.

3 0
3 years ago
I got the correct answer, but I don't know what I did. Why is the answer E?
MariettaO [177]

Explanation:

Displacement is the straight line distance from the starting position to the final position.

Person X walks halfway around circle.  So her displacement is 100 m.

Person Y walks 3/4 of the way around.  So his displacement is 50√2 m ≈ 70.7 m.

Person Z walks completely around the circle, so their displacement is 0 m.

Therefore:

Z < Y < X

6 0
2 years ago
2 Points
Mademuasel [1]

According to Newton's Second Law of Motion :

The Force acting on an Object is equal to Product of Mass of the Object and Acceleration produced due to the Force.

:\implies  Force acting = Mass of the Object × Acceleration

Given : Force = 50 newton and Mass of the Object = 10 kg

Substituting the respective values in the Formula, we get :

:\implies  50 N = 10 kg × Acceleration

:\implies \mathsf{Acceleration = \dfrac{50\;N}{10\;kg}}

:\implies Acceleration of the Object = 5 m/s²

4 0
3 years ago
The energy in the typical thunderstorm is about 1.4×1011j. a typical lightning flash transfers 30 c across a potential differenc
iragen [17]
780 seconds, or 13 minutes.

In the future, please use proper capitalization. There's a significant difference in the meaning between mV and MV. One of them indicated millivolts while the other indicates megavolts. For this problem, I'll make the following assumptions about the values presented. They are:
Total energy = 1.4x10^11 Joules (J)
Current per flash = 30 Columbs (C)
Potential difference = 30 Mega Volts (MV)

First, let's determine the power discharged by each bolt. That would be the current multiplied by the voltage, so
30 C * 30x10^6 V = 9x10^8 CV = 9x10^8 J

Now that we know how many joules are dissipated per flash, let's determine how flashes are needed.
1.4x10^11 / 9x10^8 = 1.56E+02 = 156

Since each flash takes 5 seconds, that means that it will take about 5 * 156 = 780 seconds which is about 780/60 = 13 minutes.
3 0
3 years ago
a Car with a mass of 2000 kg is moving around a circular curve at a uniform velocity of 25 m/s the curve has a radius of 80 m wh
Viefleur [7K]
Well, first of all, the car is not moving at a uniform velocity, because,
on a curved path, its direction is constantly changing.  Its speed may
be constant, but its velocity isn't.

The centripetal force on a mass 'm' that keeps it on a circle with radius 'r' is

             F = (mass) · (speed)² / (radius).

For this particular car, the force is

                    (2,000 kg) · (25 m/s)² / (80 m)

                 = (2,000 kg) · (625 m²/s²) / (80 m)

                 = (2,000 · 625 / 80)  (kg · m / s²)

                 =              15,625  newtons .
5 0
3 years ago
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