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svetoff [14.1K]
4 years ago
7

Two children weighing 17 and 25 kilograms are sitting on opposite sides of a seesaw, both 2 meters from the axis of rotation. wh

ere on the seesaw should a 10-kilogram child sit in order to achieve equilibrium?
Physics
1 answer:
Over [174]4 years ago
8 0
The principle of moments states that for a system at equilibrium the clockwise moments is equal to the anticlockwise moments.
Moments is given by force × perpendicular distance
Moments one one side of the seesaw will be 340Nm and on the other will be 500Nm, for balanced or equilibrium to be achieved the two moments should be equal.
Difference is 160 Nm, thus with a child 10 kg to balance the system, then,
Distance will be 16 nm/ 100N = 1.6 m
Threfore, a child of 10 kg should sit at a  distance of 1.6m from the pivot on the side with 17 kg child for the system to balance.
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The summer camps had a field trip from the campus to Fragrance Hill. They traveled at an average speed of 65 km/h in the first 2
ludmilkaskok [199]

Answer:

Explanation:

They traveled this distance in 2 parts, essentially. Part 1 had an average speed for a certain number of hours, part 2 had an average speed for a certain number of hours, and those 2 parts taken together took them a distance of 364 km. In equation form, that looks like this:

km/hr part 1 + km/hr part 2 = 364 km

Now we need to find each part on the left side of that equation. Part 1 first:

We traveled 65 km/hr for 2 hours, so that took us

65\frac{km}{hr}*2hr and canceling out the hour label, we have that in part 1 we got

65(2) = 130 km. Good. Now onto the second part, where our unknown is.

We traveled 78 km/hr the second part for x hours, so that took us

78\frac{km}{hr}*xhr and canceling out the hour label, we have that in part 2 we got

78x km. Now we can fill in the main equation (the one in bold print)

130 km + 78x km = 364 km and subtracting 130 km from both sides:

78x km = 234 km and dividing by 78 km:

x = 3 hours. Part 2 took 3 hours. Part 1 took 2 hours, so the whole trip took 5 hours.

7 0
3 years ago
What does a Lewis structure diagram represent?
densk [106]

Answer:

correct me if i'm wrong nut i thinks its a The atomic symbol of an element surrounded by valence electrons

Explanation:

5 0
3 years ago
Read 2 more answers
A system gains 1500 J of heat, while the internal energy of the system increases by 4500 J and the volume decreases by . Assume
Assoli18 [71]

Answer:

Hence the pressure is 3\times 10^5 Pa

Explanation:

Given data

Q=1500 J   system gains heat

ΔV=- 0.010 m^3     there is a decrease in volume

ΔU= 4500 J        internal energy decrease

We know work done is

W= Q- ΔU

=1500-4500= -3000 J

The change in the volume at constant pressure is

ΔV= W/P

there fore P = W/ΔV= -3000/-0.01= 3×10^5

Hence the pressure is 3\times 10^5 Pa

3 0
3 years ago
Buoyancy increases with the increase in the density of a) Submerged body b) Fluid​
AlekseyPX

Answer:

Submerged body

Explanation:

  • If buoyancy is greater than weight then object will float.
  • If buoyancy is less then weight then object will sink.
  • If buoyancy=weight then objects remains stable
4 0
3 years ago
A calorimeter is used to determine the specific heat capacity of a test metal. If the specific heat capacity of water is known,
denis23 [38]

Answer:

initial and final temperatures of both the water and metal, mass of the metal, and mass of the water

Explanation:

Heat lost by the metal, Q = mc(t_{2} - t_{1})

Heat gained by the water in the calorimeter, Q_{w} = m_{w}c_{w}(t_{2w} - t_{1w})

For energy to be conserved in the system, the heat lost by the metal will equal the heat gain by the water in the calorimeter.

        mc(t_{2} - t_{1}) = m_{w}c_{w}(t_{2w} - t_{1w})

Where,

m is the mass of the metal

c is specific heat capacity of the metal

t₂ is the final temperature of the metal

t₁ is the initial temperature of the metal

m_{w} is the mass of the water

c_{w} is specific heat capacity of water

t_{2w} is the final temperature of water

t_{1w} is the initial temperature of water

From the question given, specific heat capacity of the water is known, the quantities to be measured are;

Initial and final temperatures of both the water and metal,

Mass of the metal, and mass of the water

8 0
3 years ago
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