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gtnhenbr [62]
2 years ago
5

The average Wealth of a person in Richville is $150,000 and the average wealth of a

Mathematics
1 answer:
miskamm [114]2 years ago
6 0
I would assume that poorville and richville would balance out so it would come out to around 75k (if you were talking about what the income would be) in mediumville
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Im studying for my ged can you help with this ?
jarptica [38.1K]
What do you need help with on it?
6 0
3 years ago
Jamie has 100 milliliters of a 50% isopropyl alcohol solution. How many milliliters of a 96% isopropyl alcohol solution does she
serious [3.7K]

Answer:

318.2 ml

Step-by-step explanation:

Jamie has 100 ml of a 50% isopropyl alcohol solution.

She wants to prepare a solution of 85% by adding 96% solution of isopropyl alcohol solution.

Let the amount of 96% solution required = x ml

Final amount of 85% isopropyl alcohol solution = (100 + x) ml

Therefore, equation for this situation will be,

100 × (50%) + (x) × (96%) = (100 + x) × (85%)

100(0.5) + 0.96x = 0.85(100 + x)

50 + 0.96x = 85 + 0.85x

0.96x - 0.85x = 85 - 50

0.11x = 35

x = \frac{35}{0.11}

x = 318.18 ml

  ≈ 318.2 ml

Therefore, she will require 318.2 ml of 96% isopropyl alcohol solution.

4 0
3 years ago
Jose has determined he needs to have $800,000 for retirement in 30 years. His account earns 6% interest.
soldi70 [24.7K]

  • 26,666.66~ just cash a year 2,222.166666 a month but if u want interest with u haveand u make up to 1.6k off of just ur interest but a year of just multiple of 1.6k every year ud only get 48k interest in 30 years that's from nothing to to get 800,000
6 0
3 years ago
Given ƒ(x) = 14x + 42, find x when ƒ(x) = 35. A) − 12 Eliminate B) −1 C) 1 D) 3
balandron [24]

Step-by-step explanation:

f(x)=14x+42

f(x)=35

Given the information above, we can simply set up an equation so we can find the value of x.

14x + 42 = 35

Subtract 42 on both sides.

14x=-7

Divide 14 on both sides.

x=-\frac{1}{2}

So, the value of x is equal to -1/2 when f(x) is 35.

6 0
3 years ago
Find which term in the geometric sequence 1,3,9,27,... is the first to exceed 7,000.
Zielflug [23.3K]

The common ratio between terms is 3, so the sequence has general n-th term

a_n=3^{n-1}

for n\ge1. The term exceeds 7000 when

3^{n-1}>7000\implies n-1>\log_37000\implies n>1+\log_37000\approx9.06

which means the first time a_n exceeds 7000 occurs when n=10. Indeed,

a_{10}=3^{10-1}=19,683

while the previous term would have been

a_9=3^{9-1}=6561

8 0
4 years ago
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