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2 years ago

Which side of this proton transfer reaction is favored at equilibrium?

Chemistry

1 answer:

Maru [420]2 years ago

3 0

The left side proton transfer will be favored and the reactants will convert into products , Option C is the right answer.

<h3>What is Proton Transfer ?</h3>

A step in a process in which the proton is removed from one species and accepted by another species is called Proton Transfer.

It generally takes place between an acid and a base.

At equilibrium the reactants are mostly converted into products , At equilibrium the equilibrium lie towards the right side .

Therefore left side proton transfer will be favored and the reactants will convert into products.

To know more about Proton Transfer

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How many Sodium (NA) Atoms are in Methylene?

postnew [5]

Answer:

No Sodium(Na) in methylene

Explanation:

Methylene is an organic compound

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3 years ago

If the density of a certain spherical atomic nucleus is 1.0 _ 1014 g cm_3 and its mass is 2.0 _ 10_23 g, what is its radius in c

melamori03 [73]

1) Calculate the volume from d = m/V => V = m/d = 2.0*10^-23 g / 1.0*10^14 g/cm^3 = 2.0*10^-9 cm^3

2) Now use the formula of volume for a sphere: V = (4/3)π(r^3) =>

r =∛[3V/(4π)] = ∛[(3*2.0*10^-9 cm^3) / (4π)] = 0.48*10^-3 cm = 4.8*10^-4 cm = 0.00048cm

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3 years ago

Which compound is an organic acid?<br> A.CH3OH<br> B.CH3OCH3<br> C.CH3COOH<br> D.CH3COOCH3

Vinil7 [7]

Answer:

Explanation:

CH3COOH

ethanoic acid

5 0

3 years ago

Read 2 more answers

The formation of tert-butanol is described by the following chemical equation: (CH3), CBr (aq) + OH(aq) → Br" (aq) +(CH), COH(aq

Dafna11 [192]

Answer:

$(CH_3)_3С^+ (aq) + OH^- (aq)\rightarrow (CH_3)_3COH (aq)$

Explanation:

There are two ways of looking at this problem. The first way, slightly more advanced, is to understand that the carbocation formed is an intermediate in this reaction: it is formed in one step and consumed in the subsequent step.

Secondly, we have hydroxide involved as our reactant, so it should be our second reactant in the second bimolecular step.

Thirdly, the product formed would be a combination of the anion and cation, one of our products, this means we have the following second step:

$(CH_3)_3С^+ (aq) + OH^- (aq)\rightarrow (CH_3)_3COH (aq)$

Another way is to verify this knowing that by adding all of the steps should yield a net equation, notice if we add the two steps together (reactants on one side and products on the other), we obtain:

$(CH_3)_3С^+ (aq) + OH^- (aq) + (CH_3)_3CBr (aq)\rightarrow (CH_3)_3COH (aq) + (CH_3)_3C^+ (aq) + Br^- (aq)$

Notice that the intermediate carbocation cancels out on both sides to yield the final net equation:

$OH^- (aq) + (CH_3)_3CBr (aq)\rightarrow (CH_3)_3COH (aq) + Br^- (aq)$

This means we have the correct second step.

6 0

3 years ago

Which element in the periodic table does the beanie atom most closely resemble?

MrRissso [65]

Answer:

number of valence electrons

Explanation:

The chemical properties of the atoms of elements in a group of the periodic table is most closely related to the number of valence electrons. All the chemical properties can be justified just by the number of valence electrons.

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2 years ago