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stich3 [128]
2 years ago
15

Which side of this proton transfer reaction is favored at equilibrium?

Chemistry
1 answer:
Maru [420]2 years ago
3 0

The  left side proton transfer will be favored and the reactants will convert into products , Option C is the right answer.

<h3>What is Proton Transfer ?</h3>

A step in a process in which the proton is removed from one species and accepted by another species is called Proton Transfer.

It generally takes place between an acid and a base.

At equilibrium the reactants are mostly converted into products , At equilibrium the equilibrium lie towards the right side .

Therefore left side proton transfer will be favored and the reactants will convert into products.

To know more about Proton Transfer

brainly.com/question/861100

#SPJ1

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They all have the same choices but one of them its not gonna be used.​
Dima020 [189]

Answer:

limiting reactant

Explanation:

it is consumed totally

3 0
2 years ago
If the conjugate base of a molecule has a pkb of 1.4, what would you expect the molecule to be?
maw [93]

If the conjugate base of a molecule has a pKb of 1.4, the molecule should be a Weak Acid.

Notice this question gives us the pKb of the molecule, not the pKa. Because of this, the pH scale basically gets reversed, so lower numbers in pKb correlate with stronger bases, and higher numbers in pKb correlate with stronger acids - the exact opposite of the pH scale.

It's important to make sure you completely understand the terms of conjugate base, conjugate acid, pKb, pKa, and how they all relate. It's easy to mix up the meanings of these definitions.

Here are the two other pieces of information you need to know to correctly answer this question:

  • Strong acids have a weak conjugate base.
  • Strong bases have a weak conjugate acid.

So if the problem says you have a strong conjugate base, then the molecule must be a weak acid. To illustrate this, think of ammonium, NH4+. Ammonium is a weak acid, but the conjugate base of ammonium is ammonia, NH3, which is a reasonably good base.

Learn more about conjugate base here : brainly.com/question/22514615

#SPJ4

3 0
2 years ago
A piece of an unknown substance weighing 124.0 grams is heated in boiling water to 100.0oc. when the substance is placed in a ca
MakcuM [25]

The heat cause 300g water temperature increase from 20 to 26 celcius. The heat transferred would be: 300g * (26 °C -20 °C) *4.2 joule/gram °C= 7560J

The unknown substance is added to the water, so its final temperature should be the same as the water. The calculation would be:

7560J= 124g * (100-26)* specific heat

specific heat= 7560J / 124g / 74 °C= 0.8238 J/gram °C

3 0
3 years ago
Can someone plz help me? :(
Sveta_85 [38]

Answer:

it's C

Explanation:

because it exhaled the carbon dioxide

8 0
2 years ago
Which <br> molecule has the same shape and hybridization as methane
Korvikt [17]
Hi, the answer is <span>CF2Cl2 :)</span>
6 0
3 years ago
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