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jasenka [17]
3 years ago
14

What two properties of a gas depend on its container?

Chemistry
2 answers:
Bogdan [553]3 years ago
3 0

One property is it's volume. I am not sure if the second

siniylev [52]3 years ago
3 0

Answer:

Volume and pressure.

Explanation:

The gases represent the physical state of matter whose values of volume, density or shape are not defined. They have a high degree of disorder caused by the free displacement of the particles that make them up (atoms, molecules or ions - usually molecules) and are objects of study because they have great applicability in everyday life, and because they are the material layer in which we keep most contact, after all, normally our whole body is in contact with gases (atmospheric air).

The properties of the gases are variable, that is, because there are certain and specific spaces between their constituents (which can increase or decrease) the volume, density, pressure, viscosity can be changed. The smaller the container in which the gas is containing, the smaller its volume and the higher its pressure, for example.

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Answer:

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Given a gas whose temperature is 418 K at a pressure of 56.0 kPa. What is the pressure of the gas if its Temperature changes to
Rainbow [258]

Answer: P₂=0.44 atm

Explanation:

For this problem, we are dealing with temperature and pressure. We will need to use Gay-Lussac's Law.

Gay-Lussac's Law: \frac{P_{1} }{T_{1} } =\frac{P_{2} }{T_{2} }

First, let's do some conversions. Anytime we deal with the Ideal Gas Law and the different laws, we need to make sure our temperature is in Kelvins. Since T₂ is 64°C, we must change it to K.

64+273K=337K

Now, it may be uncomfortable to use kPa instead of atm, so let's convert kPa to atm.

56.0kPa*\frac{1000Pa}{1kPa} *\frac{atm}{101325Pa} =0.55atm

Since our units are in atm and K, we can use Gay-Lussac's Law to find P₂.

P_{2} =\frac{T_{2} P_{1} }{T_{1} }

P_{2}=\frac{(337K)(0.55atm)}{418K}

P₂=0.44 atm

8 0
3 years ago
What is the chemical that had polluted flints drinking water supply
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Lead

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The temperature at which the vapor pressure of a liquid is equal to normal atmospheric pressure is the _______. A. boiling point
timurjin [86]

Answer:

A. boiling point

Explanation:

The correct answer is;

A. boiling point

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B. melting point

This option is wrong because the melting point is the temperature at which a solid undergoes a phase change to a liquid.

C. freezing point

This option is wrong because the freezing point is the temperature at which a liquid undergoes a phase change to a solid.

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