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sergiy2304 [10]
3 years ago
7

Limiting Reactant:

Chemistry
1 answer:
Rufina [12.5K]3 years ago
8 0

Zn as a limiting reactant

N₂ as an excess reactant

Theoretical Yield : 13.15 g

<h3>Further explanation</h3>

Reaction

3 Zn + N₂ ⇒ Zn₃N₂

Ar Zn : 65,38 g/mol

Ar N₂ : 28.0134 g/mol

mol Zn

\tt \dfrac{11.5}{65.38}=0.176

mol N₂

\tt \dfrac{9.55}{28.0134}=0.341

limiting reactant : the smaller ratio(mol:coefficient)

mol ratio Zn : N₂ :

\tt \dfrac{0.176}{3}\div \dfrac{0341}{1}=0.0586\div 0.341

Zn as a limiting reactant(smaller ratio)

N₂ as an excess reactant

mol Zn₃N₂ :

\tt \dfrac{1}{3}\times 0.176=0.0586

mass of Zn₃N₂ (Theoretical Yield) :

\tt 0.0586\times 224.154~g/mol=13.15~g

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Answer: here is your answer

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If you are given an ideal gas with pressure (p)259,392.00 pa and temperature (T)=200°c of 1 mole Argon gas in a volume 8.8dm3,ca
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Answer: R=4.82436 \frac{Pa. m^{3}}{mol. K}

Explanation:

The Ideal Gas equation is:  

P.V=n.R.T  (1)

Where:  

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n the number of moles of gas  

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T is the absolute temperature of the gas in Kelvin.

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It is important to note that the behavior of a real gas is far from that of an ideal gas, taking into account that <u>an ideal gas is a single hypothetical gas</u>. However, under specific conditions of standard temperature and pressure (T=0\°C=273.15 K and P=1 atm=101,3 kPa) one mole of real gas (especially in noble gases such as Argon) will behave like an ideal gas and the constant R will be 8.3144598 \frac{Pa. m^{3}}{mol. K}.

However, in this case we are not working with standard temperature and pressure, therefore, even if we are working with Argon, the value of R will be far from the constant of the ideal gases.

Having this clarified, let's isolate R from (1):

R=\frac{PV}{nT}  (2)

Where:

P=259392 Pa

n=1 mole

T=200\°C=473.15 K is the absolute temperature of the gas in Kelvin.

V=8.8 dm^{3}=0.0088 m^{3}

R=\frac{(259392 Pa)(0.0088 m^{3})}{(1 mole)(473.15 K)}  (3)

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R=4.82436 \frac{Pa. m^{3}}{mol. K}  

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It is also referred to as a limiting reactant or limiting agent.

Now, according to the question,

Since it is a limiting reagent, it will react fully. 

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It is used to restrict the reaction.

It tells you the estimated amount of compound to be used.

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More information on limiting reagents can be found here :

brainly.com/question/11848702

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