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Nataly_w [17]
2 years ago
8

What mass in grams of iron metal can be formed by the reaction of 2.14 gAI metal with excess Fe₂O₃, according to the thermite re

action: 2Al(s) + Fe₂O₃ → 2Fe(s) + Al₂O₃(s)
Chemistry
1 answer:
kogti [31]2 years ago
8 0

Answer:

4.43 g Fe

Explanation:

To find the mass of iron, you need to (1) convert grams Al to moles Al (via molar mass), then (2) convert moles Al to moles Fe (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe to grams Fe (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs because the given value (2.14) has 3 sig figs.

Molar Mass (Al): 26.982 g/mol

2 Al(s) + Fe₂O₃ --->  2 Fe(s) + Al₂O₃(s)

Molar Mass (Fe): 55.845 g/mol

 2.14 g Al           1 mole              2 moles Fe           55.845 g
----------------  x  -----------------  x  --------------------  x  ------------------  =  4.43 g Fe
                         26.982 g           2 moles Al             1 mole

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Answer:

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Can can someone lease check my answers and tell me if im right???
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<span>Technically, this question is badly worded. If all 4 containers were at STP, then all 4 containers would have the same pressure. So I'll assume instead that all 4 containers are at the same temperature, and then use the ideal gas law to determine the relative internal pressures of each container.

   The idea gas law is
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  where
  P = Pressure
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    Since all the containers are at the same temperature, we can ignore the R and T parts of the formula and substitute some value K for constant. So we get PV = nK

   Now solve for P
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   From the above, you can see that the pressure is proportional to the number of moles divided by the volume. So let's calculate that value for each container.
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Container C: 1 / 22.4 = 0.044642857
Container D: 2 / 11.2 = 0.178571429
   So as you can see, the pressures in containers A and C are the same, which is the first available option, so you are correct.</span>
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