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Phoenix [80]
2 years ago
11

Based on probability and if it is appropriate for a decision to be left up to chance, choose every situation that is both statis

tically fair and morally fair.
Situation #1 A high school student is deciding whether to first clean his room or do his homework. He decides by picking a tile at random from a bag of lettered tiles. If he picks a consonant he will clean his room, and if he picks a vowel he will do his homework.
Situation #2 There are four candidates eligible for a vacancy at a company. Ignoring qualifications and experience, the recruitment manager decides which candidate to hire by writing their names on pieces of paper, shuffling the papers, and drawing one at random.
Situation #3 Five cousins are deciding which board game to play. They each write their preferred game on a different section of a spinner that has five equally-sized sections. They spin the spinner and will play the game written on the section where the spinner lands.
Situation #4 To determine who can choose the spot for a picnic, Kate picks a tile at random from a collection of five tiles, numbered 2 through 6. Kate chooses the spot if she picks a prime number, and Charles chooses if Kate picks a composite number.
Situation #5 Five roommates all want to attend an event, but they only have four invites. To decide who will attend, they shuffle a set of five cards consisting of four aces and a king. Each roommate is randomly dealt a card. The ones dealt an ace will attend the event.
Reset Next
Mathematics
1 answer:
svet-max [94.6K]2 years ago
4 0

The situations that are both statistically fair and morally fair are Situation 2, Situation 3 and Situation 5

<h3>How to categorize the situations?</h3>

For a situation to be fair, the probability of every outcome must be equal.

We can now analyze each option using the above highlight

<u>Situation 1</u>

  • Alphabets = 26
  • Probability of vowel = 5/26
  • Probability of consonant = 21/26

The probabilities of vowels and consonant are not equal.

Hence, this situation is not fair

<u>Situation 2</u>

People = 4

P(Each) = 1/4

The probability of each participant is equal in the above scenario i.e. 1/4

Hence, this situation is fair

<u>Situation 3</u>

  • People = 5
  • P(Each) = 1/5

The probability of each cousin is equal in the above scenario i.e. 1/5

Hence, this situation is fair

<u></u>

<u>Situation 4</u>

  • Numbers = 5 i.e. 2 to 6
  • P(Prime) = 3/5
  • P(Composite) = 4/6

The probabilities of prime and composite numbers are not equal.

Hence, this situation is not fair

<u>Situation 5</u>

  • Roommates = 5
  • Cards = 5
  • Aces = 4
  • P(Each) = 1/5

All probabilities are equal in the above scenario i.e. 1/5

Hence, this situation is fair

Read more about probability at:

brainly.com/question/251701

#SPJ1

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Procedure:

1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
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Solution

1) the number of teams of four members that can be formed are:

10*9*8*7 / (4*3*2*1) = 210

2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls

Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6

Number of different teams with 2 boys and 2 girls = 15 * 6 = 90

3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:

90/210 = 3/7
 
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Step-by-step explanation:

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