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Phoenix [80]
3 years ago
11

Based on probability and if it is appropriate for a decision to be left up to chance, choose every situation that is both statis

tically fair and morally fair.
Situation #1 A high school student is deciding whether to first clean his room or do his homework. He decides by picking a tile at random from a bag of lettered tiles. If he picks a consonant he will clean his room, and if he picks a vowel he will do his homework.
Situation #2 There are four candidates eligible for a vacancy at a company. Ignoring qualifications and experience, the recruitment manager decides which candidate to hire by writing their names on pieces of paper, shuffling the papers, and drawing one at random.
Situation #3 Five cousins are deciding which board game to play. They each write their preferred game on a different section of a spinner that has five equally-sized sections. They spin the spinner and will play the game written on the section where the spinner lands.
Situation #4 To determine who can choose the spot for a picnic, Kate picks a tile at random from a collection of five tiles, numbered 2 through 6. Kate chooses the spot if she picks a prime number, and Charles chooses if Kate picks a composite number.
Situation #5 Five roommates all want to attend an event, but they only have four invites. To decide who will attend, they shuffle a set of five cards consisting of four aces and a king. Each roommate is randomly dealt a card. The ones dealt an ace will attend the event.
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Mathematics
1 answer:
svet-max [94.6K]3 years ago
4 0

The situations that are both statistically fair and morally fair are Situation 2, Situation 3 and Situation 5

<h3>How to categorize the situations?</h3>

For a situation to be fair, the probability of every outcome must be equal.

We can now analyze each option using the above highlight

<u>Situation 1</u>

  • Alphabets = 26
  • Probability of vowel = 5/26
  • Probability of consonant = 21/26

The probabilities of vowels and consonant are not equal.

Hence, this situation is not fair

<u>Situation 2</u>

People = 4

P(Each) = 1/4

The probability of each participant is equal in the above scenario i.e. 1/4

Hence, this situation is fair

<u>Situation 3</u>

  • People = 5
  • P(Each) = 1/5

The probability of each cousin is equal in the above scenario i.e. 1/5

Hence, this situation is fair

<u></u>

<u>Situation 4</u>

  • Numbers = 5 i.e. 2 to 6
  • P(Prime) = 3/5
  • P(Composite) = 4/6

The probabilities of prime and composite numbers are not equal.

Hence, this situation is not fair

<u>Situation 5</u>

  • Roommates = 5
  • Cards = 5
  • Aces = 4
  • P(Each) = 1/5

All probabilities are equal in the above scenario i.e. 1/5

Hence, this situation is fair

Read more about probability at:

brainly.com/question/251701

#SPJ1

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2/3 (x + 13) =22<br><br>what is x ?
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