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Phoenix [80]
2 years ago
11

Based on probability and if it is appropriate for a decision to be left up to chance, choose every situation that is both statis

tically fair and morally fair.
Situation #1 A high school student is deciding whether to first clean his room or do his homework. He decides by picking a tile at random from a bag of lettered tiles. If he picks a consonant he will clean his room, and if he picks a vowel he will do his homework.
Situation #2 There are four candidates eligible for a vacancy at a company. Ignoring qualifications and experience, the recruitment manager decides which candidate to hire by writing their names on pieces of paper, shuffling the papers, and drawing one at random.
Situation #3 Five cousins are deciding which board game to play. They each write their preferred game on a different section of a spinner that has five equally-sized sections. They spin the spinner and will play the game written on the section where the spinner lands.
Situation #4 To determine who can choose the spot for a picnic, Kate picks a tile at random from a collection of five tiles, numbered 2 through 6. Kate chooses the spot if she picks a prime number, and Charles chooses if Kate picks a composite number.
Situation #5 Five roommates all want to attend an event, but they only have four invites. To decide who will attend, they shuffle a set of five cards consisting of four aces and a king. Each roommate is randomly dealt a card. The ones dealt an ace will attend the event.
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Mathematics
1 answer:
svet-max [94.6K]2 years ago
4 0

The situations that are both statistically fair and morally fair are Situation 2, Situation 3 and Situation 5

<h3>How to categorize the situations?</h3>

For a situation to be fair, the probability of every outcome must be equal.

We can now analyze each option using the above highlight

<u>Situation 1</u>

  • Alphabets = 26
  • Probability of vowel = 5/26
  • Probability of consonant = 21/26

The probabilities of vowels and consonant are not equal.

Hence, this situation is not fair

<u>Situation 2</u>

People = 4

P(Each) = 1/4

The probability of each participant is equal in the above scenario i.e. 1/4

Hence, this situation is fair

<u>Situation 3</u>

  • People = 5
  • P(Each) = 1/5

The probability of each cousin is equal in the above scenario i.e. 1/5

Hence, this situation is fair

<u></u>

<u>Situation 4</u>

  • Numbers = 5 i.e. 2 to 6
  • P(Prime) = 3/5
  • P(Composite) = 4/6

The probabilities of prime and composite numbers are not equal.

Hence, this situation is not fair

<u>Situation 5</u>

  • Roommates = 5
  • Cards = 5
  • Aces = 4
  • P(Each) = 1/5

All probabilities are equal in the above scenario i.e. 1/5

Hence, this situation is fair

Read more about probability at:

brainly.com/question/251701

#SPJ1

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Likurg_2 [28]

Answer:

must be greater than 7

Step-by-step explanation:

using pythagoras theorem

a^2=b^2-c^2

x^2=15^2-12^2

x^2=225-144

x^2=81

take square root both sides

√x^2=√81

x=9

and 9 is greater than 7

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3 years ago
Graph the inverse circular function by hand, given f(x) = 3sin(2x) ;-pi/4 ≤ ≤pi/4
nasty-shy [4]

Part a)

a) The given function is

f(x) = 3 \sin(2x)

We let

y =  3 \sin(2x)

Interchange x and y.

x=  3 \sin(2y)

Solve for y;

\frac{x}{3}  =  \sin(2y)

y =  \frac{1}{2}  { \sin}^{ - 1}( \frac{x}{3} )

{f}^{ - 1}(x)  =  \frac{1}{2}  { \sin}^{ - 1}( \frac{x}{3} )

Part b) The range of f(x) refers to y-values for which f(x) exists.

The range of f(x) is

-  3 \leqslant y \leqslant 3

This is because the function is within y=-3 and y=3.

c) The range of

{f}^{ - 1} (x)

is

-  \frac{ \pi}{4}  \leqslant y \leqslant  \frac{\pi}{4}

The domain is -3≤x≤3

This is because the domain and range of a function and its inverse swaps.

Part d) The graph is shown in the attachment.

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Answer:

y=-6x+10

Step-by-step explanation:

The point of intersection of

x+2y=9...eqn1


and


4x-2y=-4...eqn2

is the solution of the two equations.


We add equation (1) and equation(2) to get,

x+4x+2y-2y=9+-4


\Rightarrow 5x=5


\Rightarrow x=1

We put x=1 into equation (1) to get,

1+2y=9

\Rightarrow 2y=9-1

\Rightarrow 2y=8

\Rightarrow y=4


Therefore the line passes through the point, (1,4).


The line also passes through the point of intersection of

3x-4y=14...eqn(3)

and

3x+7y=-8...eqn(4)

We subtract equation (3) from equation (4) to obtain,

3x-3x+7y--4y=-8-14


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We substitute this value into equation (4) to get,

3x+7(-2)=-8


3x-14=-8


3x=-8+14


3x=6

x=2

The line also passes through

(2,-2)



The slope of the line is

slope=\frac{4--2}{1-2} =\frac{6}{-1}=-6


The equation of the line is

y+2=-6(x-2)

y+2=-6x+12


y=-6x+10 is the required equation





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Answer:

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Step-by-step explanation:

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