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Inessa [10]
3 years ago
11

Calvin types 4 pages in 1/5 hour. The average page contains 250 words. What is Calvin's approximate typing speed in words per mi

nute?
Mathematics
1 answer:
RoseWind [281]3 years ago
7 0

Answer:

83 1/3 words per minute

or approximately 83 words per minute

Step-by-step explanation:

4 pages * 250 words/ page = 1000 words

1/5 hour * 60 minutes/ 1 hour = 12 minutes

1000 words / 12 minutes = 83.333333333.... words per minute

83 1/3 words per minute


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Step-by-step explanation:

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Please help me. 5(m-7)=-8(3m+8)
inessss [21]

Answer:

m = -1

Step-by-step explanation:

Solve for m:

5 (m - 7) = -8 (3 m + 8)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the left hand side:

5 m - 35 = -8 (3 m + 8)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the right hand side:

5 m - 35 = -24 m - 64

Hint: | Move terms with m to the left hand side.

Add 24 m to both sides:

24 m + 5 m - 35 = (24 m - 24 m) - 64

Hint: | Look for the difference of two identical terms.

24 m - 24 m = 0:

24 m + 5 m - 35 = -64

Hint: | Group like terms in 24 m + 5 m - 35.

Grouping like terms, 24 m + 5 m - 35 = (5 m + 24 m) - 35:

(5 m + 24 m) - 35 = -64

Hint: | Add like terms in 5 m + 24 m.

5 m + 24 m = 29 m:

29 m - 35 = -64

Hint: | Isolate terms with m to the left hand side.

Add 35 to both sides:

29 m + (35 - 35) = 35 - 64

Hint: | Look for the difference of two identical terms.

35 - 35 = 0:

29 m = 35 - 64

Hint: | Evaluate 35 - 64.

35 - 64 = -29:

29 m = -29

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 29 m = -29 by 29:

(29 m)/29 = (-29)/29

Hint: | Any nonzero number divided by itself is one.

29/29 = 1:

m = (-29)/29

Hint: | Reduce (-29)/29 to lowest terms. Start by finding the GCD of -29 and 29.

The gcd of -29 and 29 is 29, so (-29)/29 = (29 (-1))/(29×1) = 29/29×-1 = -1:

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3 years ago
How do you do this question?
r-ruslan [8.4K]

Step-by-step explanation:

y = 3 + 8x^(³/₂), 0 ≤ x ≤ 1

dy/dx = 12√x

Arc length is:

s = ∫ ds

s = ∫₀¹ √(1 + (dy/dx)²) dx

s = ∫₀¹ √(1 + (12√x)²) dx

s = ∫₀¹ √(1 + 144x) dx

If u = 1 + 144x, then du = 144 dx.

s = 1/144 ∫ √u du

s = 1/144 (⅔ u^(³/₂))

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Substitute back:

s = 1/216 (1 + 144x)^(³/₂)

Evaluate between x=0 and x=1.

s = [1/216 (1 + 144)^(³/₂)] − [1/216 (1 + 0)^(³/₂)]

s = 1/216 (145)^(³/₂) − 1/216

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skelet666 [1.2K]

Answer:

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Slope = (y2 - y1)/(x2 - x1)

= (2-2)/(4-(-2))

= 0

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2 years ago
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