Answer:
equation;
Center (-4,2)
Radius is
Step-by-step explanation:
Since the x^2 and y^2 have the same coeffiecent this will be a circle in a form of
Where (h,k) is center
r is the radius
So first we group like Terms together
Add 7 to both sides
Since the orginal form of the equation of the circle has a perfect square we need to complete the square for each problem
and
so we have
To find our center, h is -4 and k is 2
so the center is (-4,2)
The radius is
So the radius is 3 times sqr root of 3.
2/9 is already simplified but it’s decimal form is
_
0.2
12/3=4
so m=4
6x4=24
6x1=6
24-6=18
Answer:
x³ - 8x² - 11x + 148
Step-by-step explanation:
Given that x = 6 + i is a root then x = 6 - i is also a root
Complex roots occur as conjugate pairs.
The factors are therefore (x - (6 + i)) and(x - (6 - i))
Given x = - 4 is a root then (x + 4) is a factor
The polynomial is the product of the factors, that is
p(x) = (x + 4)(x - (6 + i))(x - (6 - i))
= (x + 4)(x - 6 - i)(x - 6 + i)
= (x + 4)((x - 6)² - i²)
= (x + 4)(x² - 12x + 36 + 1)
= (x + 4)(x² - 12x + 37) ← distribute
= x³ + 4x² - 12x² - 48x + 37x + 148
= x³ - 8x² - 11x + 148
3.15. Just find the unit rate which is 1.5 and multiply that by 3
