I believe you meant to say that if Samantha bought 510 pounds of hamburger, how much will she pay?
Now from the information we already have, we know that 3 pounds of hamburger will cost 6 dollars.
The next thing we need to know is how much one pound of hamburger will cost. This will help us calculate how much the rest will cost.
we now form an equation to assist us.
3 = 6
1= x
(where x represents the unknown price of one pound of hamburger)
Now we must cross-multiply:
3 * x = 6 x 1
3x = 6
x = 6/3
x = 2
therefore one pound of hamburger costs 2 dollars.
Now, If one pound costs 2 dollars, how about 510 pounds?
We simply multiply: 510 x 2 = 1,020
Therefore Samantha will pay 1, 020 dollars for 510 pounds of hamburger.
Answer:
A # is odd
Step-by-step explanation:
Hypothesis-----> conclusion
Answer: 15 girls
Step-by-step explanation:
27 - 3 = 24
24/2 = 12
12 boys
12 + 3 = 15
15 girls
15+ 12 = 27
Answer:
1) (x + 3)(3x + 2)
2) x= +/-root6 - 1 by 5
Step-by-step explanation:
3x^2 + 11x + 6 = 0 (mid-term break)
using mid-term break
3x^2 + 9x + 2x + 6 = 0
factor out 3x from first pair and +2 from the second pair
3x(x + 3) + 2(x + 3)
factor out x+3
(x + 3)(3x + 2)
5x^2 + 2x = 1 (completing squares)
rearrange the equation
5x^2 + 2x - 1 = 0
divide both sides by 5 to cancel out the 5 of first term
5x^2/5 + 2x/5 - 1/5 = 0/5
x^2 + 2x/5 - 1/5 = 0
rearranging the equation to gain a+b=c form
x^2 + 2x/5 = 1/5
adding (1/5)^2 on both sides
x^2 + 2x/5 + (1/5)^2 = 1/5 + (1/5)^2
(x + 1/5)^2 = 1/5 + 1/25
(x + 1/5)^2 = 5 + 1 by 25
(x + 1/5)^2 = 6/25
taking square root on both sides
root(x + 1/5)^2 = +/- root(6/25)
x + 1/5 = +/- root6 /5
shifting 1/5 on the other side
x = +/- root6 /5 - 1/5
x = +/- root6 - 1 by 5
x = + root6 - 1 by 5 or x= - root6 - 1 by 5
Answer:
Coordinates switch, and the new y-coordinate changes sign
Explanation:
We have point A with the coordinates (-1,2), when we rotate it c90º it becomes (2,1).
What happened? The coordinates switched and the x-coordinate of A (-1) became the y-coordinate of A' (1) and it changed its sign.
