Which best describes the spread of a set of data that has an interquartile range of 14 and a mean absolute deviation of 6? The correct answer is letter (D) "<span>The average distance of all data values from the mean is 14 and the middle 50% of data values has a range of 6."</span>
Diameter of the bigger semi-circle is 15 m
circumference of the bigger semi-circle = πd = 15π
diameter of the smaller semi-circle = 15 - 2(1.25) = 15 - 2.5 = 12.5 m
circumference of the smaller semi-circle = πd = 12.5π m
Total length of the segments between the two circles = 11(1.25) = 13.75 m
Total length of wrought iron used = 15π + 12.5π + 13.75 = 100 m
Answer:
75 in^2
Step-by-step explanation:
The surface area is the sum of the areas
Area of the square:
A = s^2 = 5^2 =25
Area of one triangle
A = 1/2 bh = 1/2 (5)(5) = 25/2
There are 4 triangles
4* (26)/2 = 50
The sum is 25+50 = 75
80% of x = 16
"of" translates to multiplication and 80% becomes 80/100.
80/100 × x = 16
0.8x = 16
0.8x/0.8 = 16/0.8
x = 16/0.8
x = 20
Your final answer is 80% of 20 is 16.
