The coordinates of the pre-image of point F' is (-2, 4)
<h3>How to determine the coordinates of the pre-image of point F'?</h3>
On the given graph, the location of point F' is given as:
F' = (4, -2)
The rule of reflection is given as
Reflection across line y = x
Mathematically, this is represented as
(x, y) = (y, x)
So, we have
F = (-2, 4)
Hence, the coordinates of the pre-image of point F' is (-2, 4)
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Answer: 0.475 cups of broth per serving.Explanation:1) Ratio given: i) To facilitate the operations, transform the mixed number 4 3/4 cups into improper fraction:
4 + 3/4 = [16 + 3] / 4 = 19 / 4
ii) ratio broth: servings
2) Proportion with the unknown number of cups of broth per serving:
3) Solve for the unknown:x = [19 / 4] cups × 1 serving / 10 servings = 19 / 40 cups = 0.475 cups
Answer:
5x^2 ( x^2 -2)(x^2 +2)(x^2+2x+2)(x^2-2x+2)
Step-by-step explanation:
5x^10 − 80x^2
The greatest common factor is 5x^2
5x^2 ( x^8 - 16)
Rewriting the parentheses
5x^2 ( x^4 ^2 - 4^2)
We notice the difference of squares (a^2 -b^2) = (a-b)(a+b)
5x^2 ( x^4 -4)(x^4+4)
Again rewriting the first parentheses
5x^2 ( x^2 ^2 -2^2)(x^4+4)
5x^2 ( x^2 -2)(x^2 +2)(x^4+4)
The last term can be rewritten as(x^2+2x+2)(x^2-2x+2)
5x^2 ( x^2 -2)(x^2 +2)(x^2+2x+2)(x^2-2x+2)
510 = (1700)(6)(t)
510 = 10200t
0.05 = T