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rodikova [14]
3 years ago
7

18 + x = 10 x=____ help

Mathematics
2 answers:
hodyreva [135]3 years ago
7 0

Answer:

X=-8

Step-by-step explanation:

18+x=10

-18 -18

x=-8

masya89 [10]3 years ago
7 0


x = -8 i think I’m not sure.
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lozanna [386]
Sure!! Tell me the equation :)
5 0
3 years ago
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if you are just given the two points it is the same formula. Find the midpoint between the points (4,−5) and (−4,5).
adell [148]

Answer:

M = (0,0)

Step-by-step explanation:

Given

(4,-5) and (-4,5)

Required

The midpoint (M)

This is calculated as:

M = \frac{1}{2}(x_1 + x_2,y_1+y_2)

So, we have:

M = \frac{1}{2}(4-4,-5+5)

M = \frac{1}{2}(0,0)

M = (0,0)

3 0
3 years ago
On February 10, 1990, high tide in Boston was at midnight. The water level at high tide was 9.9 feet; later, at low tide, it was
Verizon [17]

Answer:

a) Model

H(t)=4.9cos(\frac{\pi}{6}t)+5

b) The tide will be at 6.5 ft high at 2:24 am (going down).

As the tide will rise again, the tide will be again at 6.5 ft high at 9:36 am (going up).

c) H(10 am) = 7.45

H(4 pm) = 2.55

Step-by-step explanation:

We can model this as a sine or cosine wave, for which we will calculate its parameters by the data given.

The model we will use is:

H(t)=Acos(\omega t+\phi)+B

t will be in hours, starting from midnight (t=0)

1) We know that at midnight happens the high tide. That means that

H(0)=Acos(\omega* 0+\phi)+B=A+B=9.9\\\\ \phi=0\\\\A+B=9.9

2) Six hours later (t=6) happens the low tide (0.1 ft)

H(0)=Acos(\omega*6)+B=-A+B=0.1\\\\\\ cos(\omega*6)=-1,\, \omega=\pi/6\\\\\\B=0.1+A=9.9-A\\\\2A=9.9-0.1\\\\A=9.8/2=4.9\\\\\\B=0.1+A=0.1+4.9=5

Now that we have calculated all the parameters, the model for the height of the tide is:

H(t)=4.9cos(\frac{\pi}{6}t)+5

On Feb 10, when is the water level 6.5 feet high?

H(t)=4.9cos(\frac{\pi}{6}t)+5=6.5\\\\cos(\frac{\pi}{6}t)=(6.5-5)/4.9=0.306\\\\t=\frac{6}{\pi}arcos(0.306)=2.4

The tide will be at 6.5 ft high at 2:24 am (going down).

As the tide will rise again, the tide will be again at 6.5 ft high at 9:36 am (going up).

On Feb 10, what is the water level at 10 am? 4pm?

At 10 am is t=10:

H(10)=4.9cos(\frac{\pi}{6}10)+5=4.9*0.5+5=2.45+5=7.45

At 4 pm, is t=12+4=16

H(16)=4.9cos(\frac{\pi}{6}16)+5=4.9*(-0.5)+5=-2.45+5=2.55

3 0
3 years ago
Can someone help me with this math problem
kondaur [170]
19.125 mi  is the answer

5 0
4 years ago
What is 0.083 repeting as a percentage?
Pachacha [2.7K]

0.083 as a percentage would be 8.3% with a horizontal bar on top of the three. This is to indicate that it is repeating. To find percentage when you have a decimal, multiply a decimal by 100. If it is a fraction, divide the numerator by the denominator and you get a decimal. Then multiply it by 100 to get the percent.

<em>Hope it helps      </em>

8 0
4 years ago
Read 2 more answers
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