All categories

3 years ago

18 + x = 10 x=____ help

Mathematics

2 answers:

hodyreva [135]3 years ago

7 0

Answer:

X=-8

Step-by-step explanation:

18+x=10

-18 -18

x=-8

masya89 [10]3 years ago

7 0

x = -8 i think I’m not sure.

You might be interested in

Help!!! Please!! Thank you!

Assoli18 [71]

1.014)x=24 hope it helps

4 0

4 years ago

Identify the factors of the terms of the expression of 13m-2n

Alex Ar [27]

Hi it is 7n I hope I was right

4 0

3 years ago

1) What is the area of square of length 5cm?

ASHA 777 [7]

Answer:

20 is my answer and the question is somehow confusing

7 0

2 years ago

2logx=3-2log(x+3) solve for x

AVprozaik [17]

Answer:

$\large\boxed{x=\dfrac{-3+\sqrt{40+10\sqrt{10}}}{2}}$

Step-by-step explanation:

$2\log x=3-2\log(x+3)\\\\Domain:\ x>0\ \wedge\ x+3>0\to x>-3\\\\D:x>0\\============================\\2\log x=3-2\log(x+3)\qquad\text{add}\ 2\log(x+3)\ \text{to both sides}\\\\2\log x+2\log(x+3)=3\qquad\text{divide both sides by 2}\\\\\log x+\log(x+3)=\dfrac{3}{2}\qquad\text{use}\ \log_ab+\log_ac=\log_a(bc)\\\\\log\bigg(x(x+3)\bigg)=\dfrac{3}{2}\qquad\text{use the de}\text{finition of a logarithm}\\\\x(x+3)=10^\frac{3}{2}\qquad\text{use the distributive property}$

$x^2+3x=10^{1\frac{1}{2}}\\\\x^2+3x=10^{1+\frac{1}{2}}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\x^2+3x=10\cdot10^\frac{1}{2}\qquad\text{use}\ \sqrt[n]{a}=a^\frac{1}{n}\\\\x^2+3x=10\sqrt{10}\qquad\text{subtract}\ 10\sqrt{10}\ \text{from both sides}\\\\x^2+3x-10\sqrt{10}=0\\\\\text{Use the quadratic formula}\\\\ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\a=1,\ b=3,\ c=-10\sqrt{10}\\\\b^2-4ac=3^2-4(1)(-10\sqrt{10})=9+40\sqrt{10}\\\\x=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2(1)}=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2}\\\\x=\dfrac{-3-\sqrt{10+10\sqrt{10}}}{2}\notin D$

6 0

3 years ago

How much time is needed for a 15,000 W engine to do 1,800,000 J of work? (Power: P = W/t) 0.008 s 8 s 120 s 1,785,000 s

Thepotemich [5.8K]

By definition, the power is given by:
$P = \frac{W}{t}$
By definition, the power is given by:
Where,
W: Work done
t: time
Clearing the time we have:
$t = \frac{W}{P}$
Substituting values we have:
$t = \frac{1800000}{15000}$
Making the corresponding calculations we have:
$t = 120s$
Answer:
is needed for a 15,000 W engine to do 1,800,000 J of work about:
$t = 120s$

7 0

3 years ago

Read 2 more answers