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MariettaO [177]
3 years ago
9

The missing expressions and output values on Jenna's table

Mathematics
1 answer:
Tanya [424]3 years ago
8 0
Jenna writes 5 fewer facts than Cleo.  Let "c" = number of facts Cleo writes.
So an expression we can use to figure out how many facts Jenna writes is:

c - 5

So the table could look something like this:
10 ║ c-5 ║ 5
11  ║ c-5 ║ 6
12 ║ c-5 ║ 7

So if Cleo writes 31 facts, we can still use: c - 5 
Plug in c = 31 to get:
31 - 5 = 26 facts for Jenna


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Answer:

Part a. t = 7.29 years.

Part b. t = 27.73 years.

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Part b. It is given that p = $2000, r = 2.5%, and A = $4000. In this part, t is unknown. Therefore: 4000 = 2000*e^(2.5t). This implies 2 = e^(0.025t). Taking natural logarithm on both sides yields ln(2) = ln(e^(0.025t)). A logarithmic property is that the power of the logarithmic expression can be shifted on the left side of the whole expression, thus multiplying it with the expression. Therefore, ln(2) = 0.025t*ln(e). Since ln(e) = 1, and making t the subject gives t = ln(2)/0.025. This means that t = 27.73 years (rounded to the nearest 2 decimal places)!!!

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