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NISA [10]
1 year ago
15

qrt{5}" align="absmiddle" class="latex-formula"> simplify this
Mathematics
2 answers:
SSSSS [86.1K]1 year ago
6 0

\sqrt{29 \:  -  \: 12 \sqrt{5} }

  • Factor the indicated expression:

\sqrt{(3 \:  -  \: 2 \sqrt{5}) ^{2}  }

  • Simplified the index the root and also the exponent using the number 2.

\boxed{ \bold{2 \sqrt{5}  \:  -  \: 3}}

<h3><em><u>MissSpanish</u></em> </h3>
Andrej [43]1 year ago
3 0

\large\displaystyle\text{$\begin{gathered}\sf \sqrt{29-12\sqrt{5}} \end{gathered}$}

<u>                                                        </u>

<u />\large\displaystyle\text{$\begin{gathered}\sf =\sqrt{20-12\sqrt{5}+9} \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf =\sqrt{4\cdot \:5-12\sqrt{5}+9} \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf =\sqrt{\left(\sqrt{4}\right)^2\left(\sqrt{5}\right)^2-12\sqrt{5}+\left(\sqrt{9}\right)^2} \end{gathered}$}

<u>                                                                                      </u>

<u />\large\displaystyle\text{$\begin{gathered}\sf \sqrt{4}=2  \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \sqrt{9}=3  \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf 2\cdot2\cdot3\sqrt{5}=12\sqrt{5}   \end{gathered}$}

<u>                                                                                       </u>

<u />\large\displaystyle\text{$\begin{gathered}\sf =\sqrt{2^2\left(\sqrt{5}\right)^2-2\cdot \:2\cdot \:3\sqrt{5}+3^2} \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Apply\:the\:formula\:from\:binomial\:to\:square:(a-b)^2=a^2-2ab+b^2 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf 2^{2}(\sqrt{5})^{2}-2\cdot2\cdot3\sqrt{5}+3^{2}=(2\sqrt{5}-3)^{2}    \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf =\sqrt{\left(2\sqrt{5}-3\right)^2} \end{gathered}$}

<u>                                                                                           </u>

<u />\large\displaystyle\text{$\begin{gathered}\sf Apply \ the \ laws \ of \ exponents:\sqrt[n]{a^{2} }=a  \end{gathered}$}

\sqrt{(2\sqrt{5}-3)^{2}    } =2\sqrt{5 }-3.

\red{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \red{=2\sqrt{5}-3  } \end{gathered}$}}} \ \ \red{\Rightarrow} \ \ \bf{\red{Answer}}

↓

\red{\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\red{MyHeritage}} \end{gathered}$}}}}

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\dfrac{a}{b}=0.75.

Step-by-step explanation:

If two equations a_1x+b_1y+c_1=0 and a_2x+b_2y+c_2=0 has infinitely many solutions, then

\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}

The given equations are

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\dfrac{a}{3}=\dfrac{b}{4}=\dfrac{1}{2}

Now,

\dfrac{a}{3}=\dfrac{1}{2} and \dfrac{b}{4}=\dfrac{1}{2}

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a=1.5 and b=2

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Now,

\dfrac{a}{b}=\dfrac{1.5}{2}=0.75

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The rate on a cell phone is $0.22 per minute. If Izzy uses her phone for 2 hours, how much does she pay?
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$26.4

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Step-by-step explanation:

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b. simply multiply the price of one pair of jeans, as found above, by 8. 23.80*8 is $190.4 for 8 jeans

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