The odds of expected outcomes of a physical characteristic in a particular breeding
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Answer:
Allele frequency
Normal allele
Mutant r allele
Genotype frequency
Homozygous normal bugs
Homozygous mutant bug
Heterozygous normal bug with one mutant r allele and one normal allele
Explanation:
It is given that 99% of the bugs were killed after the spray of pyrethrum. This suggests that 1% of the bugs that were not killed must be homozygous for the mutant type allele "r"
Thus, the frequency of homozygous "rr" species i.e
From this we can evaluate the frequency of mutant "r" allele.
Thus,
As per Hardy-Weinberg first equilibrium equation,
Substituting the value of q in above equation, we get
Thus, the frequency of homozygous normal bug is equal to
As per Hardy-Weinberg second equilibrium equation-
Substituting all the available values we get -
Allele frequency
Normal allele
Mutant r allele
Genotype frequency
Homozygous normal bugs
Homozygous mutant bug
Heterozygous normal bug with one mutant r allele and one normal allele