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GREYUIT [131]
2 years ago
10

Write an explicit formula for an, the nth term of the sequence 33, 30, 27

Mathematics
1 answer:
lawyer [7]2 years ago
8 0

Answer:

<u>aₙ = aₙ₋₁ - 3</u>

Step-by-step explanation:

Given :

First term : <u>33</u>

Common difference = 30 - 33 = <u>-3</u>

<u />

============================================================

Then the formula will be :

<u>aₙ = aₙ₋₁ - 3</u>

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HELP ASAP ROCKY!!!!!!
vekshin1

Answer:

32.5

Step-by-step explanation:

there are 4 rows

1  = 3

2 =  5

3 =  2

so there is 10 numbers

We go for the middle number which is 2-3 so the answer must be 32.5.

We know it is between 2-3 as the same as 1-10

1,2,3,4,5, ------ 6,7,8,9,10

So the imput numbers are listed 2 + 3 in your stem diagram where so 5 + 6 would be in the explanation. As 10 +1 = 11  then 11/2 = 5.5  - this means 5.5 = 32.5 as 33 would be the 6.

8 0
3 years ago
Read 2 more answers
What are the solution(s) to the quadratic equation 50 – x2 = 0?
timofeeve [1]

Answer:

No real solution

Step-by-step explanation:

Work is on another question for this. You have asked it multiple times

8 0
3 years ago
Read 2 more answers
Can sum1 help me with this asap pls :)
IrinaVladis [17]
5 units (extra characters......)
8 0
3 years ago
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Round 543,982 to the nearest thousand.
Ratling [72]

Answer:

544,000

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Can someone help please
myrzilka [38]
<h3>Answer:   15x^(7/3) - 8x^(7/4) + x + 9000</h3>

=========================================================

Explanation:

If you know the cost function C(x), to find the marginal cost, we apply the derivative.

Marginal cost = derivative of cost function

Marginal cost = C ' (x)

Since we're given the marginal cost, we'll apply the antiderivative (aka integral) to figure out what C(x) is. This reverses the process described above.

\text{Cost} = \text{antiderivative of marginal cost}\\\\\displaystyle C(x) = \int \left(35x^{4/3} - 14x^{3/4} + 1\right)dx\\\\

C(x) = \frac{1}{1+4/3}*35x^{4/3+1} - \frac{1}{1+3/4}*14x^{3/4+1} + x + D\\\\C(x) = \frac{1}{7/3}*35x^{7/3} - \frac{1}{7/4}*14x^{7/4} + x + D\\\\C(x) = \frac{3}{7}*35x^{7/3} - \frac{4}{7}*14x^{7/4} + x + D\\\\C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\

D represents a fixed constant. I would have used C as the constant of integration, but it's already taken by the cost function C(x).

To determine the value of D, we plug in x = 0 and C(x) = 9000. This is because we're told the fixed costs are $9000. This means that when x = 0 units are made, you still have $9000 in costs to pay. This is the initial value. You'll find that all of this leads to D = 9000 because everything else zeros out.

Therefore, we go from this

C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\

to this

C(x) = 15x^{7/3} - 8x^{7/4} + x + 9000\\\\

which is the final answer.

3 0
2 years ago
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