(a + 1)(a² + 2a + 1)
= a(a² + 2a + 1) + 1(a² + 2a + 1)
= a³ + 2a² + a + a² + 2a + 1
= a³ + 3a² + 3a + 1
Answer: b
perimeter =QR+RS+ST+TU+UQ =26.1
RQ = 5.39
RS = 4.47
ST = 3.61
TU = 4.12
UQ = 8.54
Answer:
or 
Step-by-step explanation:
Given

Required
Solve for x using:

First, we need to identify a, b and c
The general form of a quadratic equation is:

So, by comparison with 

Substitute these values of a, b and c in




Split the expression to two
or 
To solve further in decimal form, we have
or 
or 
or 
It is easier to compare a positive number and a negative number because it’s just like regular adding
Answer:
a. 4 : 1
b. 2 students
c. 3 : 1
Step-by-step explanation:
a. There were 12 students who got a C and 3 students who got As. The ratio is therefore:
12 : 3
Take it to the lowest form by dividing both sides by 3:
= 4 : 1
b. There were 4 students with a D grade and 8 with a B. The ratio is:
= 4 : 8
Taken to the lowest form that would be:
= 1 : 2
This means that for every student receiving a D, 2 students received an A.
c. 12 students received a C and 4 students received a D. That ratio is therefore:
= 12 : 4
Take to the lowest form by dividing both sides by 4:
= 3 : 1