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3241004551 [841]
2 years ago
6

ABC Corp. has 2,000 bonds outstanding with a $1,000 face value, an 9 percent coupon, 8 years to maturity, annual interest paymen

ts, and sells at $1,105.38. The firm also has 40,000 shares of common stock outstanding at a market price of $85 a share and a beta of 0.67. The risk-free rate is 4 percent, the market return is 15 percent, and the tax rate is 20 percent. What is WACC?
Mathematics
1 answer:
Airida [17]2 years ago
8 0

The value of WACC is 6.72%

<h3>what is WACC?</h3>

WACC is calculated by multiplying the cost of each capital source (debt and equity) by its relevant weight by market value, and then adding the products together to determine the total.

WACC=[(Market value of Equity*cost of equity+ Market value of Debt* post tax cost of debt)/(Market value of Equity+ Market value of Debt)]

Market value of Equity= 40,000*$85=$3,400,000

Cost of equity=Risk free return+ Beta equity*market retrun

=4 +0.67*15

=7.35

Market value of Debt

=2000*1105.38

=2,210,760

Post tax rate of debt

=9*80(1-20)

=0.0576= 5.76%

WACC= [$3,400,000* 7.35+ 2,210,760 *  5.76%]\ $3,400,000+2,210,760

=6.72%

Learn more about this concept here:

brainly.com/question/14774411

#SPJ1

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The probability that your call to a service line is answered in less than 30 seconds is 0.75. Assume that your calls are indepen
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Answer:

a) 0.2581

b) 0.4148

c) 17

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.75

a. If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is P(X = 9) when n = 12. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{12,9}.(0.75)^{9}.(0.25)^{3} = 0.2581

b. If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is P(X \geq 16) when n = 20

So

P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 16) = C_{20,16}.(0.75)^{16}.(0.25)^{4} = 0.1897

P(X = 17) = C_{20,17}.(0.75)^{17}.(0.25)^{3} = 0.1339

P(X = 18) = C_{20,18}.(0.75)^{18}.(0.25)^{2} = 0.0669

P(X = 19) = C_{20,19}.(0.75)^{19}.(0.25)^{1} = 0.0211

P(X = 20) = C_{20,20}.(0.75)^{20}.(0.25)^{0} = 0.0032

So

P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.1897 + 0.1339 + 0.0669 + 0.0211 + 0.0032 = 0.4148

c. If you call 22 times, what is the mean number of calls that are answered in less than 30 seconds? Round your answer to the nearest integer.

The expected value of the binomial distribution is:

E(X) = np

In this question, we have n = 22

So

E(X) = 22*0.75 = 16.5

The closest integer to 16.5 is 17.

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