What is the largest integer that is below square root of 7?

Mathematics

2 answers:

Butoxors [25]2 years ago

7 0

Answer:

Step-by-step explanation:

Thats your answerrrrrr

Stella [2.4K]2 years ago

7 0

√7＝2.64575
∴the largest integer that is below square root of 7 is 2

Hope my answer helped u :)

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${\boxed{\mathcal{\purple{D.\:81}}}}$ ✅

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

$( {3})^{ \frac{11}{5} } \div {3}^{ \frac{ - 9}{5} } \\ \\=( {3})^{ \frac{11}{5} - ( \frac{ - 9}{5} ) } \\ \\ = ( {3})^{ \frac{11}{5} + \frac{9}{5} } \\ \\ = ( {3})^{ \frac{11 + 9}{5} } \\ \\ = ( {3})^{ \frac{20}{5} } \\ \\ = ( {3})^{4} \\ \\ = ( \: 3 \times 3 \times 3 \times 3 \: ) \\ \\ = 81$