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Fudgin [204]
2 years ago
13

Tyler’s cell phone plan costs $350 to start, then there is a $50 charge each month. on the same grid as Hana plan, graph the cos

t of Tyler’s cell phone plan over a period of two years. Describe how the two graphs are the same and how they are different
Mathematics
1 answer:
yaroslaw [1]2 years ago
8 0

Based on the graphs representing Tyler and Hana's cell phone plans, we can say that:

  • They are similar because their slopes are the same.
  • They are different because their y-intercepts are different.

<h3>How are the graphs related?</h3>

Hana's plan has a $50 monthly charge which is the same as Tyler's. This means that Tyler and Hana's graph will have the same slope because their total amounts are changing by the same amount.

Tyler's y-intercept would be $350 which was the starting point of his plan and Hana's y-intercept would be $250. Their intercepts would therefore be different.

Rest of the question is:

Hana's cell phone plan costs $200 to start. Then there is a $50 charge each month.

Find out more on the y-intercept and the slope at brainly.com/question/27271404.

#SPJ1

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Use the figure to find the measures of the numbered angles,
Galina-37 [17]

Given:

A figure in which a transversal line t intersect the two parallel lines a and b.

To find:

The measure of the numbered angles.

Solution:

If a transversal line intersect the two parallel lines, then

1. Corresponding angles are equal.

2. Alternate interior angles are equal.

3. Alternate exterior angles are equal.

Now,

m\angle 1+99^\circ=180^\circ              (Linear pair)

m\angle 1=180^\circ-99^\circ

m\angle 1=81^\circ

m\angle 2=99^\circ                         (Vertically opposite angles)

m\angle 3=\angle 1=81^\circ                (Vertically opposite angles)

m\angle 4=99^\circ                         (Corresponding angles)

m\angle 5=\angle 3=81^\circ                (Alternate interior angles)

m\angle 6=99^\circ                         (Alternate exterior angles)

m\angle 7=\angle 3=81^\circ                (Corresponding angles)

Therefore, \angle 1=81^\circ, \angle 2=99^\circ,\angle 3=81^\circ, \angle 4=99^\circ,\angle 5=81^\circ, \angle 6=99^\circ,\angle 7=81^\circ.

8 0
3 years ago
Find the number of real number solutions for the equation. x2 + 5x + 7 = 0 0 cannot be determined 1 2
alisha [4.7K]

\Delta=5^2-4\cdot1\cdot7=25-28=-3

\Delta so 0 solutions.

5 0
3 years ago
Read 2 more answers
$300 at 5% annual interest for 7 years
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$5125.78. For simple questions like this you can search them on google and find answers very quickly so you dont waste points btw.
6 0
3 years ago
Write an equation for the cubic polynomial function whose graph has zeroes at 2, 3, and 5.
TiliK225 [7]

we know that

For a polynomial, if x=a is a zero of the function, then (x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.

So

In this problem

If the cubic polynomial function has zeroes at 2, 3, and 5

then

the factors are

(x-2)\\ (x-3)\\ (x-5)

Part a) Can any of the roots have multiplicity?

The answer is No

If a cubic polynomial function has three different zeroes

then

the multiplicity of each factor is one

For instance, the cubic polynomial function has the zeroes

x=2\\ x=3\\ x=5

each occurring once.

Part b) How can you find a function that has these roots?

To find the cubic polynomial function multiply the factors and equate to zero

so

(x-2)*(x-3)*(x-5)=0\\ (x^{2} -3x-2x+6)*(x-5)=0\\ (x^{2} -5x+6)*(x-5)=0\\ x^{3} -5x^{2} -5x^{2} +25x+6x-30=0\\ x^{3}-10x^{2} +31x-30=0

therefore

the answer Part b) is

the cubic polynomial function is equal to

x^{3}-10x^{2} +31x-30=0

7 0
3 years ago
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Alonzo describes a histogram as having a cluster from 20–50, a frequency of 0 from 10–20, and a peak at 40–50. Which histogram i
Ilia_Sergeevich [38]

Answer:

A

Step-by-step explanation:

In the histogram described by the first option, the peak (18) is located at 40-50. Also, a frequency of zero is observed for range 10-20. The cluster from 20–50 means that most of the data is between this range, in fact, only 1 point is located at range 0 - 10, outside this cluster.

8 0
3 years ago
Read 2 more answers
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