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Vinvika [58]
2 years ago
8

There are 3 red pens, 4 blue pens, 2 Blac pens, and 5 green pens in drawer, suppose you choose a pen at random

Mathematics
2 answers:
Alenkasestr [34]2 years ago
6 0

Answer:

1. 3/14

2. 2/7

3. 1/7

4. 5/14

5. 11/14

6. 9/14

Step-by-step explanation:

first get the total number of pens

3 red pens + 4 blue pens + 2 black pens + 5 green pens =

14 total number of pens

1. What is the probability that the pen chosen red?

3 red pens out of a total of 14 pens = 3/14

2. What is the probability that the pen chosen is blue?

4 blue pens out of a total of 14 pens = 4/14 -> simplified -> 2/7

3. What is the probability that the pen chosen is black?

2 black pens out of a total of 14 pens = 2/14 -> simplified -> 1/7

4. What is the probability that the pen chosen is green?

5 green pens out of a total of 14 pens = 5/14

5. What is the probability that the pen chosen is NOT red?

of the 3 red pens, 4 blue pens, 2 black pens and 5 green pens

4 blue pens, 2 black pens and 5 green pens are NOT red

4 blue pens + 2 black pens + 5 green pens =

11 total number of pens that are NOT red

11 total number of pens that are NOT red out of a total of 14 pens = 11/14

6. What is the probability that the pen chosen is NOT green?

of the 3 red pens, 4 blue pens, 2 black pens and 5 green pens

the 3 red pens, 4 blue pens, 2 black pens are NOT green

3 red pens + 4 blue pens + 2 black pens =

9 total number of pens that are NOT green

9 total number of pens that are NOT green out of a total of 14 pens = 9/14

gathmath.com

goldenfox [79]2 years ago
3 0

<u>Given :-</u>

  • Red pens = 3
  • Blue pens = 4
  • Black pens = 2
  • Green pens = 5

>> Total no. of outcomes = 3 + 4 + 2 + 5

>> Total no. of outcomes = 3 + 4 + 7

>> Total no. of outcomes = 10 + 4

>> Total no. of outcomes = 14

<u>Solution 1 :-</u>

We know,

  • P (E) = No. of possible outcomes / Total number of outcomes.

As there are three red pens. Therefore,

  • P(E) = 3 / 14

<u>Solution 2 :-</u>

We know,

  • P (E) = No. of possible outcomes / Total number of outcomes.

As there are four blue pens. Therefore,

  • P(E) = 4 / 14

<u>Solution 3 :-</u>

We know,

  • P (E) = No. of possible outcomes / Total number of outcomes.

As there are two black pens. Therefore,

  • P(E) = 2 / 14

<u>Solution 4 :-</u>

We know,

  • P (E) = No. of possible outcomes / Total number of outcomes.

As there are five green pens. Therefore,

  • P(E) = 5 / 14

<u>Solution</u><u> </u><u>5 :-</u>

We know,

  • P (E) = No. of possible outcomes / Total number of outcomes.

As there 11 pens that are not red (Green + black + blue).

  • P (E) = 11 / 14

<u>Solution</u><u> </u><u>6</u><u> </u><u>:</u><u>-</u>

We know,

  • P (E) = No. of possible outcomes / Total number of outcomes.

As there are 9 pens that are not green (Red + blue + black).

  • P (E) = 9 / 14

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