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2 years ago

The quadratic function

Mathematics

1 answer:

olga2289 [7]2 years ago

7 0

Answer:

The maximum revenue that can be generated is $128.13

Step-by-step explanation:

we have

$R(p)=-5.2p^{2}+65p-75$

where

R(p) represent the amount of revenue in dollars

p the product price

This is a vertical parabola open downward

The vertex represent a maximum

The y-coordinate of the vertex represent the maximum revenue that can be generated

Solve by graphing

using a graphing tool

Graph the quadratic equation

The vertex is the point (6.25,128.125)

see the attached figure

the y-coordinate of the vertex is 128.125

therefore

The maximum revenue that can be generated is $128.13

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Answer:

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Step-by-step explanation:

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2 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

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$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

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2 years ago

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Step-by-step explanation:

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