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Alexxx [7]
2 years ago
15

What is the smallest time interval in which a 5.7 T magnetic field can be turned on or off if the induced emf around the patient

's body must be kept to less than 0.12 V ?
Physics
1 answer:
VLD [36.1K]2 years ago
3 0

The smallest time interval in which the magnetic field can be turned on or off to induced the emf is 47.5 s.

<h3>Emf induced in the coil</h3>

The emf induced in the coil is calculated as follows;

emf = dФ/dt

where;

  • dФ is change in flux
  • dt is change in time

0.12 = 5.7/dt

dt = 5.7/0.12

dt = 47.5 s

Thus, the smallest time interval in which the magnetic field can be turned on or off to induced the emf is 47.5 s.

Learn more about emf here: brainly.com/question/13744192

#SPJ11

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melomori [17]

If the field is in a vacuum, the magnetic field is the dominant factor determining the motion. Since the magnetic force is perpendicular to the direction of travel, a charged particle follows a curved path in a magnetic field. The particle continues to follow this curved path until it forms a complete circle. Another way to look at this is that the magnetic force is always perpendicular to velocity, so that it does no work on the charged particle. The particle’s kinetic energy and speed thus remain constant. The direction of motion is affected but not the speed.

A negatively charged particle moves in the plane of the paper in a region where the magnetic field is perpendicular to the paper (represented by the small × ’s—like the tails of arrows). The magnetic force is perpendicular to the velocity, so velocity changes in direction but not magnitude. The result is uniform circular motion.

4 0
3 years ago
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Ipatiy [6.2K]
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5 0
3 years ago
The position of a car at time t is given by the function p(t)=t2 2t−4. What is the velocity when p(t)=11? assume t≥0
AysviL [449]

The velocity when function p(t)=11 is 8 .

According to the question

The position of a car at time t  represented by function :

p(t)=t^{2} +2t-4

Now,

When  function p(t) = 11 , t will be

p(t)=t^{2} +2t-4

11 = t²+2t-4

0 = t² + 2t - 15

or

t² +2t-15 = 0

t² +(5-3)t-15 = 0

t² +5t-3t-15 = 0

t(t+5)-3(t+5) = 0

(t-3)(t+5) = 0  

t = 3 , -5  

as t cannot be -ve as given ( t≥0)

so,

t = 3

Now,

the velocity when p(t)=11

As we know velocity = \frac{position}{time}

therefore to get the value of velocity from  function p(t)

we have to differentiate the function with respect to time

\frac{d(p(t))}{dt} =\frac{d}{dt} (t^{2} +2t-4)

v(t) = 2t + 2  

where v(t) = velocity at that time

as t = 3 for  p(t)=11  

so ,

v(t) = 2t + 2  

v(t) = 2*3 + 2  

v(t) = 8

Hence, the velocity when function p(t)=11 is 8 .

To know  more about function here:

brainly.com/question/12431044

#SPJ4

4 0
2 years ago
Which of the following is a difference between a mercury barometer and an aneroid barometer?
melomori [17]
They are made of different substances
7 0
3 years ago
Carry out the following calculation. Express your answer in the correct number of significant figures.
77julia77 [94]

Answer:

43.1 g

Explanation:

Density, d is defined as the mass per unit volume of an object. Density is therefore expressed as

d=m/v

Here, m is mass and v is the volume

Making mass the subject of the formula

Mass, m=dv

The volume, v is given by

V=lwh

Substituting lwh for v in the equation for mass then mass, m=dlwh

Substituting 2.6 g/cm3 for d, 4.0 cm for l, 1.8 m for w and 2.3 for h then the mass of the block will be

M=2.6*4*1.8*2.3=43.056 g

Expressing it in 1 decimal place, mass is approximately 43.1 g

3 0
3 years ago
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