The acceleration of the box is approximately
Explanation:
According to Newton's second law of motion, the net force acting on the box is equal to the product between its mass and its acceleration:
where
is the net force
m = 12.0 kg is the mass of the box
a is the acceleration
The net force can be written as
where
is the applied forward force
is the friction force
Combining the two equations,
And solving for the acceleration,
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Answer:
W = 55.12 J
Explanation:
Given,
Natural length = 6 in
Force = 4 lb, stretched length = 8.4 in
We know,
F = k x
k is spring constant
4 = k (8.4-6)
k = 1.67 lb/in
Work done to stretch the spring to 10.1 in.
W = 55.12 J
Work done in stretching spring from 6 in to 10.1 in is equal to 55.12 J.
Answer:
Distance covered by B is 4 times distance covered by A
Explanation:
For an object in free fall starting from rest, the distance covered by the object in a time t is
where
s is the distance covered
g is the acceleration due to gravity
t is the time elapsed
In this problem:
- Object A falls through a distance during a time t, so the distance covered by object A is
- Object B falls through a distance during a time 2t, so the distance covered by object B is
So, the distance covered by object B is 4 times the distance covered by object A.