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Aloiza [94]
3 years ago
12

During a new moon, the moon is between the

Physics
1 answer:
mylen [45]3 years ago
5 0
The moon is between the sun and earth.


The side where the light from the sun hits the moon is facing away from earth.
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An electric field with a magnitude of 6.0 × 104 N/C is directed parallel to the positive y axis. A particle with a charge q = 4.
jekas [21]

Answer:

Electric force, F=2.88\times 10^{-14}\ N

Explanation:

It is given that,

Magnitude of electric field, E=6\times 10^4\ N/C

Charge, q=4.8\times 10^{-19}\ C

The electric field is directed parallel to the positive y axis. We need to find the  force on the charge particle. It is given by :

F=q\times E

F=4.8\times 10^{-19}\ C\times 6\times 10^4\ N/C

F=2.88\times 10^{-14}\ N

So, the electric force on the charge is 2.88\times 10^{-14}\ N. Hence, this is the required solution.

5 0
4 years ago
The object distance for a concave lens is 8.0 cm, and the image distance is 12.0 cm. The height of the object is 4.0 cm. What is
swat32
The answer for this question, If I am correct, should be answer "D".
3 0
3 years ago
Read 2 more answers
An athlete runs four laps of a 400 m track. What is the athlete's total displacement?​
sasho [114]

Answer:

○ 0 \checkmark

Explanation:

Even if the athelete runs four laps of a 400 m track, its displacement will be 0 because the displacement is the shortest distance from its to final position. And, here the final and initial position is same since he comes to its initial position after covering certain distance. So, displacement is 0.

7 0
3 years ago
A sphere of radius 5.15 cm and uniform surface charge density +12.1 µC/m2 exerts an electrostatic force of magnitude 35.9 ✕ 10-3
rosijanka [135]
The radius of the sphere is r=5.15 cm=0.0515 m, and its surface is given by
A=4 \pi r^2 = 4 \pi (0.0515 m)^2 = 0.033 m^2

So the total charge on the surface of the sphere is, using the charge density 
\rho=+1.21  \mu C/m^2 = +1.21 \cdot 10^{-6} C/m^2:
Q= \rho A = (+1.21 \cdot 10^{-6} C/m^2)(0.033 m^2)=4.03 \cdot 10^{-8}C

The electrostatic force between the sphere and the point charge is:
F=k_e  \frac{Qq}{r^2}
where
ke is the Coulomb's constant
Q is the charge on the sphere
q=+1.75 \muC = +1.75 \cdot 10^{-6}C is the point charge
r is their separation

Re-arranging the equation, we can find the separation between the sphere and the point charge:
r=\sqrt{ \frac{k_e Q q}{F} }= \sqrt{ \frac{(8.99 \cdot 10^9 Nm^2 C^{-2})(4.03 \cdot 10^{-8} C)(1.75 \cdot 10^{-6}C)}{35.9 \cdot 10^{-3}N} }=0.133 m=13.3 cm
8 0
3 years ago
Which of the following is not an example of bias
neonofarm [45]

Answer:

B

Explanation:

The writers are from a trusted source that is considered impartial. The message is backed up by scientific investigation, and the writers have no monetary gain from their message.

5 0
3 years ago
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