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2 years ago

9

PLS HELP FIRST CORRECT ANSWER GETS BRAINLEIST

2 answers:

Aleks [24]2 years ago

5 0

The answer will be 168 cm2

Wewaii [24]2 years ago

4 0

Answer: 168cm^2

Step-by-step explanation:

lets split this into two shapes:

a rectangle and a triangle

Formulas:

rect: b * h

Tri: (b*h)/2

Solve:

12 * 10 = 120

(12*8)/2 = 48

120 + 48 =

168cm^2

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You have 42 ft. of fencing (1 ft. segments) to make a rectangular garden. How much should each side be to maximize your total ar

Verizon [17]

Answer:

$Length=10.5\ ft$

$Width=10.5\ ft$

$Area=110.25\ ft^{2}$

Step-by-step explanation:

Let

x----> the length of the rectangular garden

y---> the width of the rectangular garden

we know that

The perimeter of the rectangle is equal to

$P=2(x+y)$

we have

$P=42\ ft$

so

$42=2(x+y)$

simplify

$21=(x+y)$

$y=21-x$ ------> equation A

Remember that the area of rectangle is equal to

$A=xy$ ----> equation B

substitute equation A in equation B

$A=x(21-x)$

$A=21x-x^{2}$ ----> this is a vertical parabola open downward

The vertex is a maximum

The y-coordinate of the vertex is the maximum area

The x-coordinate of the vertex is the length side of the rectangle that maximize the area

using a graphing tool

The vertex is the point $(10.5,110.25)$

see the attached figure

so

$x=10.5\ ft$

Find the value of y

$y=21-10.5=10.5\ ft$

The garden is a square

the area is equal to

$A=(10.5)(10.5)=110.25\ ft^{2}$ ----> is equal to the y-coordinate of the vertex is correct

6 0

2 years ago

Write the decimal number in standard form<br><br> Six and five hundred and sixteen ten-thousandths

schepotkina [342]

6.516 is the number in standard form

5 0

2 years ago

The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct

lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

$y=\dfrac{x}{1+x}$

Point $P\left(1,\dfrac{1}{2}\right)$ lies on the curve.

Point $Q\left(x,\dfrac{x}{1+x}\right)$ is an arbitrary point on the curve.

The slope of the secant line PQ is

$\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]$

1. If x=0.5, then the slope is

$\dfrac{1}{2(0.5+1)}=\dfrac{1}{3}\approx 0.3333$

2. If x=0.9, then the slope is

$\dfrac{1}{2(0.9+1)}=\dfrac{1}{3.8}\approx 0.2632$

3. If x=0.99, then the slope is

$\dfrac{1}{2(0.99+1)}=\dfrac{1}{3.98}\approx 0.2513$

4. If x=0.999, then the slope is

$\dfrac{1}{2(0.999+1)}=\dfrac{1}{3.998}\approx 0.2501$

5. If x=1.5, then the slope is

$\dfrac{1}{2(1.5+1)}=\dfrac{1}{5}\approx 0.2$

6. If x=1.1, then the slope is

$\dfrac{1}{2(1.1+1)}=\dfrac{1}{4.2}\approx 0.2381$

7. If x=1.01, then the slope is

$\dfrac{1}{2(1.01+1)}=\dfrac{1}{4.02}\approx 0.2488$

8. If x=1.001, then the slope is

$\dfrac{1}{2(1.001+1)}=\dfrac{1}{4.002}\approx 0.2499$

7 0

2 years ago

Need Help ASAP WILL GIVE BRAINLIEST

Bad White [126]

Answer:

D) Distribute Property

Step-by-step explanation:

The student did Distribute property but they didn't mark it down.

3 0

2 years ago

The vertex of this parabola is at (3,-2). when the x-value is 4, the y-value is 3. whatis the coefficient of the squared express

zubka84 [21]

Answer:

<em>The coefficient of the squared expression in the parabolas equation will be 5.</em>

Step-by-step explanation:

<u>The vertex form of parabola</u> is: $y=a(x-h)^2 +k$ , where $(h,k)$ is the vertex point and $a$ is the coefficient of $x^2$ term.

The vertex is given as $(3,-2)$ . That means, $h=3$ and $k=-2$

So, the vertex form will be: $y=a(x-3)^2-2$

Given that, when the x-value is 4, the y-value is 3. So, plugging these values into the above equation, we will get.....

$3=a(4-3)^2-2\\ \\ 3=a(1)^2-2\\ \\ a=3+2=5$

Thus, the coefficient of the squared expression in the parabolas equation will be 5.

5 0

3 years ago

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