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Snowcat [4.5K]
2 years ago
9

PLS HELP FIRST CORRECT ANSWER GETS BRAINLEIST​

Mathematics
2 answers:
Aleks [24]2 years ago
5 0
The answer will be 168 cm2
Wewaii [24]2 years ago
4 0

Answer: 168cm^2

Step-by-step explanation:

lets split this into two shapes:

a rectangle and a triangle

Formulas:

rect: b * h

Tri: (b*h)/2

Solve:

12 * 10 = 120

(12*8)/2 = 48

120 + 48 =

168cm^2

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You have 42 ft. of fencing (1 ft. segments) to make a rectangular garden. How much should each side be to maximize your total ar
Verizon [17]

Answer:

Length=10.5\ ft

Width=10.5\ ft

Area=110.25\ ft^{2}

Step-by-step explanation:

Let

x----> the length of the rectangular garden

y---> the width of the rectangular garden

we know that

The perimeter of the rectangle is equal to

P=2(x+y)

we have

P=42\ ft

so

42=2(x+y)

simplify

21=(x+y)

y=21-x------> equation A

Remember that the area of rectangle is equal to

A=xy ----> equation B

substitute equation A in equation B

A=x(21-x)

A=21x-x^{2}----> this is a vertical parabola open downward

The vertex is a maximum

The y-coordinate of the vertex is the maximum area

The x-coordinate of the vertex is the length side of the rectangle that maximize the area

using a graphing tool

The vertex is the point (10.5,110.25)

see the attached figure

so

x=10.5\ ft

Find the value of y

y=21-10.5=10.5\ ft

The garden is a square

the area is equal to

A=(10.5)(10.5)=110.25\ ft^{2} ----> is equal to the y-coordinate of the vertex is correct

6 0
3 years ago
Write the decimal number in standard form<br><br> Six and five hundred and sixteen ten-thousandths
schepotkina [342]
6.516 is the number in standard form
5 0
3 years ago
The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct
lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

y=\dfrac{x}{1+x}

Point P\left(1,\dfrac{1}{2}\right) lies on the curve.

Point Q\left(x,\dfrac{x}{1+x}\right) is an arbitrary point on the curve.

The slope of the secant line PQ is

\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]

1. If x=0.5, then the slope is

\dfrac{1}{2(0.5+1)}=\dfrac{1}{3}\approx 0.3333

2. If x=0.9, then the slope is

\dfrac{1}{2(0.9+1)}=\dfrac{1}{3.8}\approx 0.2632

3. If x=0.99, then the slope is

\dfrac{1}{2(0.99+1)}=\dfrac{1}{3.98}\approx 0.2513

4. If x=0.999, then the slope is

\dfrac{1}{2(0.999+1)}=\dfrac{1}{3.998}\approx 0.2501

5. If x=1.5, then the slope is

\dfrac{1}{2(1.5+1)}=\dfrac{1}{5}\approx 0.2

6. If x=1.1, then the slope is

\dfrac{1}{2(1.1+1)}=\dfrac{1}{4.2}\approx 0.2381

7. If x=1.01, then the slope is

\dfrac{1}{2(1.01+1)}=\dfrac{1}{4.02}\approx 0.2488

8. If x=1.001, then the slope is

\dfrac{1}{2(1.001+1)}=\dfrac{1}{4.002}\approx 0.2499

7 0
3 years ago
Need Help ASAP WILL GIVE BRAINLIEST
Bad White [126]

Answer:

D) Distribute Property

Step-by-step explanation:

The student did Distribute property but they didn't mark it down.

3 0
2 years ago
The vertex of this parabola is at (3,-2). when the x-value is 4, the y-value is 3. whatis the coefficient of the squared express
zubka84 [21]

Answer:

<em>The coefficient of the squared expression in the parabolas equation will be 5.</em>

Step-by-step explanation:

<u>The vertex form of parabola</u> is:  y=a(x-h)^2 +k , where (h,k) is the vertex point and a is the coefficient of x^2 term.

The vertex is given as (3,-2). That means, h=3 and k=-2

So, the vertex form will be:  y=a(x-3)^2-2

Given that, when the x-value is 4, the y-value is 3. So, plugging these values into the above equation, we will get.....

3=a(4-3)^2-2\\ \\ 3=a(1)^2-2\\ \\ a=3+2=5

Thus, the coefficient of the squared expression in the parabolas equation will be 5.

5 0
3 years ago
Read 2 more answers
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