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3 years ago

Please helppppppppppppppp fine x its high school geometry

Mathematics

1 answer:

Illusion [34]3 years ago

5 0

First take triangle BDH. We know B is 46 degrees and D is 33 degrees. Since the angles of a triangle equal 180 we get
180 - 46 - 33 = 101 for H.
H is supplementary to x, so their sum is also 180. This gives 180 - 101 = 79.
So x is 79 degrees.

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Question 3

Crank

Step-by-step explanation:

Given that,

The mass of a patient = 70 kg

A 70kg patient has approximately 8 pints of blood.

The patient donates 470mL of blood.

We know that,

1 pint = 568 mL

8 pints = 4544 mL

Required fraction,

$\dfrac{470}{4544}=0.1\\\\=\dfrac{1}{10}$

So, the required fraction is approximately $\dfrac{1}{10}$ .

4 0

2 years ago

F(x)= (x+9x2- 9x +15

Oduvanchick [21]

Answer:

10x+15

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is 99,056 divided by 52

telo118 [61]

Answer: 1,904.92308 if you round it that will be 1904.9 or 1904.92

I used a calculator

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3 years ago

KIM [24]

Hey, can you please fix this question? I can't seem to understand it. When you do, please tell me so I can help you out!

4 0

3 years ago

Which would be the best method to use to solve the following equations? Explain your reasoning.

o-na [289]

A. square root property

$3x^2-192=0\\x^2-66=0\\x^2=66\\x= -\sqrt{66} or \sqrt{66}$

it has one value with x which is x^2 and it cn be easily solved without having to factorise, quadratic formula cant be used as it need ax^2+bx+c=0 format

B. factorising

$x^2-x-6=0\\x^2+2x-3x-6=0\\(x+2)(x-3)=0\\x+2=0 and x-3=0\\x= -2 \\x= 3$

i just felt like this was easier to factorise than the other 2 options left

C. Completing the square

$x^2-6x-7=0\\(x-3)^2=0\\x= -1\\x= 7$

same reason personal preference

D- Quadratic

$x^2-17x-7=0\\x=\frac{-(-17)+\sqrt{(-17)^2-4(1)(-7)} }{2(1)} \\x=\frac{-(-17)-\sqrt{(-17)^2-4(1)(-7)} }{2(1)}\\x=17.4\\x=-0.402$

the 17 kinda threw me off and i didnt wanna get on factorising or doing completing the square so quadratic formal

7 0

2 years ago